How many degrees in fahrenheit is 6.75 degrees celsius?

Think about the sound waves and light waves that are transmitted when you use a computer, watch TV, or use your phone. How are t

serious [3.7K]

Answer:

Light and sound waves are different in the sense that:

Light can travel without a medium, and is a physical particle

Sound is a vibration in a medium

Light can be altered by a different medium

Same with sound

Explanation:

There's no answer list, but here are some answers.

8 0

3 years ago

First to answer will be the brainliest

Black_prince [1.1K]

The first one is at a higher freq

5 0

3 years ago

A superball with a mass m = 61.6 g is dropped from a height h = [02]____________________ m. It hits the floor and then rebounds

aleksklad [387]

<em>There is not enough data to solve the problem, but I'm assuming the initial height as h = 10 m for the question to have a valid answer and the student can have a reference to solve their own problem</em>

Answer:

(a) $\Delta P=1.67 \ kg.m/s$

(b) $\Delta P=0.86\ m/s$

Explanation:

<u>Change of Momentum</u>

The momentum of a given particle of mass m traveling at a speed v is given by

$P=m.v$

When this particle changes its speed to a value v', the new momentum is

$P'=m.v'$

The change of momentum is

$\Delta P=m.v'-m.v$

$\Delta P=m.(v'-v)$

Defining upward as the positive direction, we'll compute the change of momentum in two separate cases.

(a) The initial height of the superball of m=61.6 gr = 0.0616 Kg is set to h= 10 m. This information leads us to have the initial potential energy of the ball just after it's dropped to the floor:

$U=m.g.h=0.0616\cdot 9.8\cdot 10 =6.0368\ J$

This potential energy is transformed into kinetic energy just before the collision occurs, thus

$\displaystyle \frac{1}{2}mv^2=6.0368$

Solving for v

$\displaystyle v=\sqrt{\frac{6.0368\cdot 2}{0.0616}}$

$v=-14\ m/s$

This is the speed of the ball just before the collision with the floor. It's negative because it goes downward. Now we'll compute the speed it has after the collision. We'll use the new height and proceed similarly as above. The new height is

$h'=88.5\% (10)=8.85\ m$

The potential energy reached by the ball at its rebound is

$U'=m.g.h'=0.0616\cdot 9.8\cdot 8.85 =5.342568\ J$

Thus the speed after the collision is

$\displaystyle v'=\sqrt{\frac{5.342568\cdot 2}{0.0616}}$

$v'=13.17\ m/s$

The change of momentum is

$\Delta P=0.0616\cdot (13.17+14)$

$\Delta P=1.67 \ kg.m/s$

(b) If the putty sticks to the floor, then v'=0

$\Delta P=0.0616\cdot (0+14)$

$\Delta P=0.86\ m/s$

3 0

4 years ago

You walk 53 m to the north, then you turn 60° to your right and walk another 45 m. Determine the direction of your displacement

Anton [14]

Answer:

NE 60*

Explanation:

4 0

3 years ago

person holds a 0.300 kg pomegranate at the top of a tower that is 96 m high Another person holds a 0.800 kg melon next to an ope

hoa [83]

Well, for one thing, it could depend on which fruit is dropped first. You haven't mentioned that.

If they're both dropped at exactly the same time, then the melon at 32m hits the ground first.

It has nothing to do with their masses or weights. It's only a matter of which one has farther to fall. Even if it were a school-bus at 96m instead of a pomegranate, anything dropped from less than 96m would reach the ground in less time than the school-bus.

7 0

3 years ago