A comet is in an elliptical orbit around the sun. its closest approach to the sun is a distance of 4.5 1010 m (inside the orbit
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Answer:
(a)T= M2 × g, (b)T= (M1 + M2)g, (c)T= M2 (a + g) and (d)T=(M1 + M2) (a + g)
Explanation:
M1 is hanged upper and M2 is lower at Rest.
(a) For M2
T2 = Weight of the Body M2= M2 × g
(b) T1 = Weight of the Body M2 + Weight of the Body M2
T1 = M1 g + M2 g = (M1 + M2)g
M1 is hanged upper and M2 is lower at accelerated upwards ( F = T - W)
(c) For M2
⇒T = M2a + M2g = M2 (a + g)
(d) For M1
T = (M1 + M2) a + (M1 + M2) g
⇒ T = (M1 + M2) (a + g)
The sleds speed when the spring returns toits uncompressed length is v = 0.03 m/s.
<u>Explanation</u>:
Given,
force constant = 42 N/cm = 0.42 N/m, mass m = 68 kg, spring x = 0.39 m
The potential energy, U, stored in the spring is
U = 1/2 kx^2
= 1 / 2 0.42
(0.39)^2
= 0.032 J
All its potential energy has been converted into kinetic energy since it has a uncompressed length.
K = 1/2 mv^2
v = sqrt (2K / m)
= √(( 2 0.032) / 68)
v = 0.03 m/s .