Answer:
4 m/s in negative acceleration
Explanation:
Acceleration = V- U/t
Where V is the final velocity
U is the initial velocity and t is the time given.
U = 65 m/s
V= 25 m/s
T= 10 seconds
Acceleration= (25m/s - 65m/s)÷10secs
= - 40/10
= -4m/s^2
Hence, it has a negative acceleration.
Answer:
3.9 m/s
Explanation:
We are given that
Mass of car,m=
Initial velocity,u=0
Distance,s=5.9 m

Average friction force,f=
We have to find the speed of the car at the bottom of the driveway.
Net force,
Where 
Acceleration,


v=3.9 m/s
Answer:
-10.8°, or 10.8° below the +x axis
Explanation:
The x component of the resultant vector is:
x = 3.14 cos(30.0°) + 2.71 cos(-60.0°)
x = 4.07
The y component of the resultant vector is:
y = 3.14 sin(30.0°) + 2.71 sin(-60.0°)
y = -0.777
Therefore, the angle between the resultant vector and the +x axis is:
θ = atan(y / x)
θ = atan(-0.777 / 4.07)
θ = -10.8°
The angle is -10.8°, or 10.8° below the +x axis.
2.57 joule energy lose in the bounce
.
<u>Explanation</u>:
when ball is the height of 1.37 m from the ground it has some gravitational potential energy with respect to hits the ground
Formula for gravitational potential energy given by
Potential Energy = mgh
Where
,
m = mass
g = acceleration due to gravity
h = height
Potential energy when ball hits the ground
m= 0.375 kg
h = 1.37 m
g = 9.8 m/s²

Potential Energy = 5.03 joule
Potential energy when ball bounces up again
h= 0.67 m

Potential Energy = 2.46 joule
Energy loss = 5.03 - 2.46 = 2.57 joule
2.57 joule energy lose in the bounce