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Likurg_2 [28]
4 years ago
11

A comet is in an elliptical orbit around the sun. its closest approach to the sun is a distance of 4.5 1010 m (inside the orbit

of mercury), at which point its speed is 9 104 m/s. its farthest distance from the sun is far beyond the orbit of pluto. what is its speed when it is 6 1012 m from the sun?
Physics
1 answer:
barxatty [35]4 years ago
4 0

r1 = 5*10^10 m , r2 = 6*10^12 m

v1 = 9*10^4 m/s

From conservation of energy

K1 +U1 = K2 +U2

0.5mv1^2 - GMm/r1 = 0.5mv2^2 - GMm/r2

0.5v1^2 - GM/r1 = 0.5v2^2 - GM/r2

M is mass of sun = 1.98*10^30 kg

G = 6.67*10^-11 N.m^2/kg^2

0.5*(9*10^4)^2 - (6.67*10^-11*1.98*10^30/(5*10^10)) = 0.5v2^2 - (6.67*10^-11*1.98*10^30/(6*10^12))

v2 = 5.35*10^4 m/s

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Answer:

Second Choice.

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Second Choice

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2 years ago
An electric furnace runs 13 hours a day to heat a house during January (31 days). The heating element has a resistance of 7.2 an
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Answer:

cost of running the furnace during January is $5619.62

Explanation:

given data

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solution

first we get her power consumed by furnace that is

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put here value we get

Power consumed = \frac{16.7^2}{7.2}

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Power consumed by furnace in one hour is 139.445kWh

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cost of running the furnace during January is $5619.62

4 0
3 years ago
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Answer:

2Ω

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