Answer:
Explanation:
This is a simple Law of Momentum Conservation problem of the inelastic type. The equation for this is
![[m_1v_1+m_2v_2]_b=[(m_1+m_2)v]_a](https://tex.z-dn.net/?f=%5Bm_1v_1%2Bm_2v_2%5D_b%3D%5B%28m_1%2Bm_2%29v%5D_a)
Filling in:
![[1200(4.5)+2100(0)]=[(1200+2100)v]](https://tex.z-dn.net/?f=%5B1200%284.5%29%2B2100%280%29%5D%3D%5B%281200%2B2100%29v%5D)
which simplifies to
5400 + 0 = 3300v
so v = 1.6 m/s to the east, choice B
The first rule of vectors is that the horizontal and vertical components are separate. Disregarding air resistance, the only thing we have to worry about is gravity.
The appropriate suvat to use for the vertical component is v = u +at
I will take a to be -9.81, you may have to change it to be 10 if your qualification likes g to be 10.
v = 30 + (-9.81x2)
v = 30 - 19.62
=10.38m/s
Therefore we know that after 2.0 s the vertical component will be 10.38ms^-1, ie 10m/s as the answers given are all to 2sf.
The horizontal component is completely separate to the vertical component and since there is no air resistance, it will remain constant throughout the projectiles trajectory. Therefore it will remain at 40ms^-1.
Combining this together we get:
(1) vx=40m/s and vy=10m/s
Answer:
High ceilings make a room feel large and open, but they can be difficult to cool and heat. Because hot air rises, the challenge becomes trying to keep the hot air where you want it and preventing if from being wasted where you don't.
Explanation:
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