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Vikki [24]
3 years ago
7

A small metal sphere has a mass of 0.14 g and a charge of -22.0 nc . it is 10 cm directly above an identical sphere with the sam

e charge. this lower sphere is fixed and cannot move. part a what is the magnitude of the electric force between the spheres?
Physics
1 answer:
Allushta [10]3 years ago
4 0
For this problem, we use the Coulomb's law written in equation as:

F = kQ₁Q₂/d²
where
F is the electrical force
k is a constant equal to 9×10⁹ 
Q₁ and Q₂ are the charge of the two objects
d is the distance between the two objects

Substituting the values:

F = (9×10⁹)(-22×10⁻⁹ C)(-22×10⁻⁹ C)/(0.10 m)²
F = 0.0004356 N
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Answer:

minimum speed v=\sqrt({Fr}/m)}

Explanation:

Recall the formula for centripetal force;

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F=centripetal force

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To find minimum speed make v the subject of formula;

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4 0
3 years ago
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Which is more work, pushing with 115 N over 15m or lifting 20N over 10 m?
Nikitich [7]

Work = (force) x (distance)

You could look at the two cases, and see right away that
the first one has more force acting through more distance,
so it must be more work.  But since I just gave you the formula
for Work, let's calculate the amount of it for both cases:

First case:  Work = (115 N) x (15 m) =   1,725 joules

Second case:  Work = (20 N) x (10 m)  =  200 joules

The first case involves 8.625 times as much work as the second case.

3 0
3 years ago
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3. What is the velocity of a wave that has a frequency of 750 Hz and a wavelength of 45.7 cm?
sweet-ann [11.9K]

Explanation:

v=(750)(45.7)

v=34275

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v=(750)(0.457)

v=342.75

3 0
2 years ago
A circuit contains two devices that are connected in parallel. If the resistance of one of these devices is 12 ohms and the resi
finlep [7]

<u>Answer</u>

3 Ohms

<u>Explanation</u>

when the resistors are in series, the resistance in the circuit increases. For example, if two resistors, R1 and R2 are in series, the combined resistance is R1+R2.

When connected in parallel, the total resistance is the reciprocal of (1/R1 + 1/R2)

In this case the resistors are in parallel.

Total resistance = (1/12 + 1/4)⁻¹

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2 years ago
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