Answer:
time is 3333.33 min or 55.55 hr
Explanation:
given data
reactor operating = 1 MW
negative reactivity = $5
power = 1 miliwatt
to find out
how long does it take
solution
we know here power coefficient that is
power coefficient = ![\frac{10^{6} }{10^{6} }](https://tex.z-dn.net/?f=%5Cfrac%7B10%5E%7B6%7D%20%7D%7B10%5E%7B6%7D%20%7D)
power coefficient = 1
so time required to reach power is
power = reactivity × time / power coefficient + reactor operating
1 ×
= -5 t / 1 + 1 × ![10^{6}](https://tex.z-dn.net/?f=10%5E%7B6%7D)
5t =
- ![10^{-3}](https://tex.z-dn.net/?f=10%5E%7B-3%7D)
t = 199999.99 sec
so time is 3333.33 min or 55.55 hr
I guess 48 , but I’m not sure
The gunstock it’s also called stock or shoulder stock
Answer:
two people who are not going to be able to make it to class today because of the day and then I will be there at the house and then we can go