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Law Incorporation [45]
3 years ago
7

How to find yield strength of a load vs deflection?

Physics
1 answer:
liraira [26]3 years ago
6 0
Σ/ε
σ = F/A
ε = ΔL/L
F = force
A = area
L = lenght
ΔL = |old lenght - new lenght|
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A 2,294N force is applied to a 408kg mass. What is the acceleration of the mass?
Nataly_w [17]

Answer:

5.622

Explanation:

a=F/M

a=2294/408

a=5.622

8 0
3 years ago
A bullet of 5 gm is fired from a pistol of 1.5 kg. If the recoil velocity of pistol is 1.5 m/s,
Andreyy89

Answer:

-450 m/s

Explanation:

Momentum is conserved.

p₀ = p

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v = -450 m/s

6 0
3 years ago
What effect does observing a substance s physical properties have on the substance
Aneli [31]
It can be observed without changing the identity of the object.
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The octopus’s tentacle keeps _ right after it is bitten off ? a. Moving b. Breathing c. Growing
konstantin123 [22]

Answer:

The answer is A

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5 0
2 years ago
In the final situation below, the 8.0 kg box has been launched with a speed of 10.0 m/s across a frictionless surface. Find the
Murljashka [212]

Answer:

the energy of the spring at the start is 400 J.

Explanation:

Given;

mass of the box, m = 8.0 kg

final speed of the box, v = 10 m/s

Apply the principle of conservation of energy to determine the energy of the spring at the start;

Final Kinetic energy of the box = initial elastic potential energy of the spring

K.E = Ux

¹/₂mv² = Ux

¹/₂ x 8 x 10² = Ux

400 J = Ux

Therefore, the energy of the spring at the start is 400 J.

8 0
3 years ago
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