The potential energy (P.E) of the rock relative to the base of the cliff is 31,054.926 Joules..
<u>Given the following data:</u>
- Acceleration due to gravity = 9.8
![m/s^2](https://tex.z-dn.net/?f=m%2Fs%5E2)
To calculate the potential energy (P.E) of the rock relative to the base of the cliff:
<h3>What is potential energy?</h3>
Potential energy (P.E) can be defined as the energy that is possessed by an object due to its position (height) above planet Earth.
Mathematically, potential energy (P.E) is given by this formula;
![P.E = mgh](https://tex.z-dn.net/?f=P.E%20%3D%20mgh)
<u>Where:</u>
- P.E is the potential energy.
- m is the mass of an object.
- g is the acceleration due to gravity.
- h is the height of an object.
Substituting the given parameters into the formula, we have;
![P.E = 15.9 \times 9.8 \times 199.3](https://tex.z-dn.net/?f=P.E%20%3D%2015.9%20%5Ctimes%209.8%20%5Ctimes%20199.3)
P.E = 31,054.926 Joules.
Read more on potential energy here: brainly.com/question/8664733
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Explanation:
The entangled velocity of the cars after the collision is 2.7 m/s.
<h3>What is velocity?</h3>
Velocity is the rate of change of displacement. The S.I unit of velocity is m/s.
To calculate the velocity of the entangled cars after the collision, we use the formula below.
Formula:
- mu+MU = V(m+M).............. Equation 1
Where:
- m = mass of the car
- M = mass of the truck
- u = initial velocity of the car
- U = initial velocity of the truck.
- V = velocity of the entangled car after the collision.
Make V the subject of the equation.
- V = (mu+MU)/(m+M)............ Equation 2
From the question,
Given:
- m = 2000 kg
- M = 18000 kg
- u = 0 m/s (at rest)
- U = 3 m/s
Substitute these values into equation 2
- V = [(2000×0)+(18000×3)]/(2000+18000)
- V = 54000/20000
- V = 2.7 m/s.
Hence, the entangled velocity of the cars after the collision is 2.7 m/s
Learn more about velocity here: brainly.com/question/13665920
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