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tekilochka [14]
3 years ago
5

You are conducting an experiment inside an elevator that can move in a vertical shaft. A load is hung vertically from the ceilin

g on a string. The tension in the string is measured to be exactly equal to the force due to gravity on the load. No other forces are acting on the load. Which of the following statements about the elevator are correct?
i. The elevator is an inertial frame of reference.
ii. The elevator may be at rest.
iii. The elevator may be moving at a constant velocity upward.
iv. The elevator may be moving at a constant velocity downward.
v. The elevator may be accelerating.
Physics
1 answer:
mote1985 [20]3 years ago
3 0
Hi there is the one you used in my house in a while away and it looks great on my phone but I hash
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So to find the mass we must use the formula D=M/V but because we don’t have the mass, we must use the formula M=DxV

So to find volume, just multiple the length (0.4m) width (0.4m) and height (2m) and you will get 0.32m as the volume. Now multiple this volume with your given density of 2,400 kg/m and you will get 768 kg as the mass of the marble block.

Final answer: 768 kilograms (kg) as mass of the marble block.
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When an object's temperature _______, it contracts.
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Answer is- decreases
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A 3.53-g lead bullet traveling at 428 m/s strikes a target, converting its kinetic energy into thermal energy. Its initial tempe
Taya2010 [7]

Complete question:

A 3.53-g lead bullet traveling at 428 m/s strikes a target, converting its kinetic energy into thermal energy. Its initial temperature is 40.0°C. The specific heat is 128 J/(kg · °C), latent heat of fusion is 24.5 kJ/kg, and the melting point of lead is 327°C.

(a) Find the available kinetic energy of the bullet. J

(b) Find the heat required to melt the bullet. J

Answer:

Part (a) the available kinetic energy of the bullet is 323.32 J

Part (b) the heat required to melt the bullet is 216.17 J

Explanation:

Given;

mass of the bullet = 3.53 g = 0.00353 kg

velocity of the bullet = 428 m/s

initial temperature of the bullet = 40.0°C

final temperature of the bullet =  327°C

specific heat capacity, c= 128 J/(kg · °C)

latent heat of fusion, Hf  = 24.5 kJ/kg

Part (a) the available kinetic energy of the bullet. J

KE = ¹/₂ × mv²

KE = ¹/₂ × 0.00353 × 428²

     = 323.32 J

Part (b) the heat required to melt the bullet. J

This is the thermal energy required to increase the temperature of the bullet and the heat energy required to melt the bullet.

Quantity of heat required to raise the temperature of the bullet:

Q = mcΔT

   = 0.00353 × 128 × (327-40)

   = 0.00353 × 128 × 287

   = 129.68 J

Quantity of heat required to melt the bullet:

Q = mH_f

Q = 0.00353 × 24500

   = 86.49 J

TOTAL energy required to melt the bullet = 129.68 J + 86.49 J

                                                                      = 216.17 J

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The propeller of an airplane is at rest when the pilot starts the engine; and its angular acceleration is a constant value. Two
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Answer:0.318 revolutions

Explanation:

Given

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Revolutions turned in 2 s

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