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4 years ago

Please try to do it this is where we help each other

Mathematics

2 answers:

defon4 years ago

5 0

Answer:

1. x^8

2. x^8

3. 1024

4. -21a^4

5. z^10

6. -9x^7

7. 42r^7

8. b^7

9. 8a^11

10. 12p^12

Step-by-step explanation:

mr Goodwill [35]4 years ago

5 0

mark him brainlyist !!

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In a candy factory, nutty chocolate bars contain 22.0% by mass pecans. If 4.5 kg of pecans were used for candy last Tuesday, how

Zanzabum

So we know that 22% of the mass off the chocolate bars is pecans, and that 4.5kg of pecans were used. To find the mass of nutty chocolate bars made with 4.5kg of pecans we can divide the 4.5 by 22 to find 1% of the weight of nutty chocolate bars produced, then multiply it by 100 to find the full weight in kg.

So 4.5/22= 0.205 (3dp), then 0.205x100=20.5kg of nutty chocolate bars produced.

Now to convert the kgs of chocolate bars to lbs, we multiply by 2.205 (as there is approximately 2.205 lbs to 1 kg).

So 2.205x20.5kg=45.203 lbs (3dp) of nutty chocolate bars produced on Tuesday.

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3 years ago

A class of 4th graders sold tickets to their school play. Each of the 23 students in the class sold 44 tickets. The cost of each

Otrada [13]

Find the total number of tickets sold by multiplying the number of students by the number of tickets each student sold:

23 x 44 = 1012 total tickets.

Each ticket sold for $7, now multiply the total tickets sold by the price of a ticket:

1012 x 7 = $7,084 total money

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4 years ago

Read 2 more answers

Which integer represents 50 degree below zero?

Orlov [11]

Answer:

-50

Step-by-step explanation:

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3 years ago

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The distribution of passenger vehicle speeds traveling on a certain freeway in California is nearly normal with a mean of 71.5 m

Zinaida [17]

Answer:

$G = 0.007523$

The number of cars the highway patrol officer would watch before a car that is seen is $E(X) = 1.6027$

The standard deviation is $s = 0.9829$

Step-by-step explanation:

From the question we are told that

The mean is $\mu = 71.5 \ miles/hour$

The standard deviation is $\sigma = 4.75 \ miles/hour$

The speed limit is $x = 70 \ miles /hour$

Generally the probability of getting a car that is moving with speed greater than the speed limit is mathematically represented as

$p =P(X > x ) = P(X > 70) = P(\frac{X - \mu }{\sigma } > \frac{70 - 71.5 }{4.75})$

=> $p= P(X > 70) = P(\frac{X - \mu }{\sigma } > \frac{70 - 71.5 }{4.75})$

=> $p= P(X > 70) = P(\frac{X - \mu }{\sigma } > -0.31579 )$

Here

$\frac{X - \mu }{\sigma } = Z(The \ standardized \ value \ of X )$

=> $p= P(X > 70) = P(Z > -0.31579 )$

From the z-table

$p = P(Z > -0.31579 ) = 0.62392$

$p = P(X > 70) = 0.62392$

Generally the probability of getting a car that is not moving with speed greater than the speed limit is mathematically represented as

$q = 1 - p$

=> $q = 1 - 0.62392$

=> $q = 0.37608$

Generally the probability of getting 5 cars that are not speeding is mathematically represented as

$G = q^5$

=> $G = (0.37608)^5$

=> $G = 0.007523$

Generally the number of cars that the highway patrol officer is expected to watch until the first car that is speeding is gotten is mathematically represented as

$E(X) = \frac{1}{p}$