F(x) = - 55x + 330
The domain is the set of possible input-values, i.e. x-values.
You know that f(x) cannot bebigger than 330 not lower than zero, then construct the inequality:
0 ≤ f(x) ≤ 330
0 ≤ - 55x + 330 ≤ 330
Multilply by - 1 and change the inequality signs:
0 ≥ 55x - 330 ≥ -330
Add 330 to all the members
330 ≥ 55x ≥ 0
Divide by 55
6 ≥ x ≥ 0 => 0 ≤ x ≤ 6
The the possible x-values (practical domain) is all the real numbers between 0 and 6 inclusive.
Answer:
$9.86
Step-by-step explanation:
Frist you read the problem and you see that she pays $1.89 for one drink
so you write down $1.89
then 3 cookies for $0.99 so you multiply $0.99 by 3 and you get $2.97
so you write down $2.97
next 2 slices of pizza for $2.50 so you multiply 2 by $2.50 and you get $5.00
so you write that down
lastly you and the answers you wrote down and you get $9.86
Maya payed $9.86 for her order.
Step-by-step explanation:
-3+6k+11k-10-9y+5x-y-13x
-13+17k-10y-8x
-5x+6x-9x+5xy
-8x+5xy
4/5n – 1/5 = 2/5n
Add 1/5 to both sides
4/5n = 2/5n + 1/5
Subtract 2/5n from both sides
2/5n = 1/5
Divide both sides by 2/5
n = 1/2
Answer:
C. The distribution for town A is symmetric, but the distribution for
town B is negatively skewed.
Step-by-step Explanation:
From the box plots attached in the diagram below, which shows data of low temperatures for town A and town B for some days, we can compare the shapes of the box plot by visually analysing both box plots and how the data for each town is distributed.
=> For town A, the shape of the box plot is symmetric because both quartiles seem equal, and the median also divides the rectangular box into two equal halves. Both whiskers also appear to be of equal lengths.
The box plot for Town A takes a symmetric shape, and this shows a typical normal distribution of data.
=> On the other hand, Town B data distribution is different. The median seem close to the top half of the box and does not divide the box into equal halves. This shows the distribution is skewed. Since the whisker is shorter from the upper end of the box to the left side, we can infer that the distribution for Town B is skewed to the left, and it is negatively skewed.
=> The right comparison of the shapes of the box plots is "C. The distribution for town A is symmetric, but the distribution for town B is negatively skewed."