n space you would fall with an acceleration of 9.8 m/s2. What would be your velocity after 6 seconds?

Mathematics

1 answer:

alexgriva [62]3 years ago

6 0

Starting from a velocity of 0, your change in velocity over a period of 6 seconds will be ...

... (9.8 m/s²)×(6 s) = 58.8 m/s . . . . . downward, since you are "falling"

_____

Note the units of seconds in the time period cancel one of the factors of seconds in the acceleration to leave only seconds in the denominator of the result. That is confirmation that the proper math operation is being carried out, since the units of velocity are meters per second.

You might be interested in

1 of 5

Allisa [31]

Answer:

7/1296

Step-by-step explanation:

Multiply the two probabilities.

7/36 x 1/36 = 7/1296

3 0

3 years ago

Read 2 more answers

Can't figure it out!!

Zanzabum

$\bf slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ f(x_2)}}-{{ f(x_1)}}}{{{ x_2}}-{{ x_1}}}\impliedby 
\begin{array}{llll}
average\ rate\\
of\ change
\end{array}\\\\
-------------------------------\\\\
f(x)= \cfrac{1}{x} \qquad 
\begin{cases}
x_1=2\\
x_2=b
\end{cases}\implies \cfrac{f(b)-f(2)}{b-2}=-\cfrac{1}{10}
\\\\\\
\cfrac{\frac{1}{b}-\frac{1}{2}}{b-2}=-\cfrac{1}{10}\implies 
\cfrac{\frac{2-b}{2b}}{b-2}=-\cfrac{1}{10}\implies \cfrac{2-b}{2b}=-\cfrac{b-2}{10}
\\\\\\
$

$\bf \cfrac{2-b}{2b}=\cfrac{2-b}{10}\implies 20-10b=4b-2b^2\impliedby cross-multiplying
\\\\\\
2b^2-4b-10b+20=0\implies 2b^2-14b+20=0
\\\\\\
b^2-7b+10=0\implies 
(b-2)(b-5)=0\implies b=
\begin{cases}
\boxed{5}\\
2
\end{cases}$

8 0

3 years ago

Melissa said that each member of her group completed 5/12 foot of a tower for a garden display. There were 3 members in her grou

Setler [38]

A) 5/12×3=1 1/4 I know this for sure

4 0

3 years ago

Read 2 more answers

Need help quickly please!!!

Bad White [126]

Answer:

Step-by-step explanation: