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3 years ago

How can we be safe in a science laboratory

Chemistry

2 answers:

Hoochie [10]3 years ago

7 0

Googles on, gloves and clean Youre area

vfiekz [6]3 years ago

5 0

Answer:

We can be safe in a science laboratory by following all directions and wearing gloves, goggles to protect ourselves.

Explanation:

If we don't follow the rules then we might cuase a problem that we didn't want to happen and we need to wear protective gear because we need to stay safe

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More help please!?!?!?!?!

e-lub [12.9K]

It's back wards lol you need to take it right

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3 years ago

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Which species acts exclusively as spectator ions in this reaction

adelina 88 [10]

Answer:

K^+ and NO3^-

Explanation:

In a balanced ionic equation, we usually see the species that react to yield the main product in the reaction.

Consider the reaction;

Pb(NO3)2(aq) +2 KI(aq) -------> PbI2(s) + 2KNO3(aq)

The main product in this reaction is PbI2. Hence the balanced ionic equation is;

Pb^2+(aq) + 2I^-(aq) ------> PbI2(s)

Notice that K^+ and NO3^- did not participate in this reaction. All ions that are part of the molecular equation but do not participate in the ionic reaction equation are called spectator ions. Hence K^+ and NO3^- are spectator ions in this reaction as can be seen clearly above.

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3 years ago

The ionization of pure water forms _____.

Evgesh-ka [11]

Answer: The ionization of pure water forms <u><em>hydroxide and hydronium ions.</em></u>

Explanation:

Ionization is a reaction in the pure water in which water breaks down into its constituting ions that hydronium ion and hydroxide ions.

$H_2O+H_2O\rightleftharpoons H_3O^++OH^-$

One molecule of water looses its proton to form hydroxide ion and l=the lost protons get associated with another water molecule to form hydronium ion.

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2 years ago

Part A

den301095 [7]

Answer:

$n_{Cl_2}=0.3molCl_2$

Explanation:

Hello there!

In this case, according to the given chemical reaction whereas the sodium chloride is in a 2:1 mole ratio with chlorine, the required moles of the later are computed as shown below:

$n_{Cl_2}=0.6molNaCl*\frac{1molCl_2}{2molNaCl}$

So we cancel out the moles of NaCl to obtain:

$n_{Cl_2}=0.3molCl_2$

Best regards!

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2 years ago

Hans observed properties of four different waves and recorded observations about each one in his chart.

Irina18 [472]

Answer/Explanation:

Wave W is being diffracted, Wave X is being reflected, and waves Y and Z are being refracted.

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2 years ago

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