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2 years ago

Specific heat is the heat capacity of an object divided by its mass in grams.

2 answers:

6 0

True. This is because specific heat depends on the heat capacity and the unit of mass. Mass, as we know is measured by grams, so this is a correct statement.

Answer: True

shutvik [7]2 years ago

5 0

True, because molar heat capacity is the amount of heat required to raise 1 mol of a compound by 1 Kelvin. 1 mol of a compound has an equal number of grams to his molar molecular mass. Therefore, dividing it by the mass of 1 mol (aka molecular mass) is equal to amount of heat required to raise 1 gram of the substance by 1 degree Kelvin.

You might be interested in

How many uL are present in 250 mL of H20? (1 uL = 10^-6 Liters)

Vanyuwa [196]

Answer:

250000 μL

Explanation:

If 1 L = 1000 mL

Then X L = 250 mL

X = (1 × 250) / 1000 = 0.25 L

Now we can calculate the number of microliters (μL) in 0.25 L:

if 1 μL = 10⁻⁶ L

then X μL = 0.25 L

X = (1 × 0.25) / 10⁻⁶ =250000 μL

4 0

2 years ago

Which of the following best describes physical science?

Alex17521 [72]

The study of matter and energy best describes physical science. Hence, option B is correct.

<h3>What is physical science?</h3>

Physical science is the study of the inorganic world.

Physics is a branch of science that studies matter and its motion through space and time, along with related concepts such as energy and force. Physics is one of the "fundamental sciences" because of the other natural sciences (like biology, geology etc.)

Thus the study of matter and energy best describes physical science. Hence, option B is correct.

Learn more about the physical science here:

brainly.com/question/12842883

#SPJ1

3 0

2 years ago

I have 50.00 mL of 0.100 M ethyl amine (C2H5NH2). I gradually add a solution of 0.025 M nitric acid (HNO3) to the ethyl amine so

sergeinik [125]

Answer:

4.00 is the pH of the mixture

Explanation:

The ethyl amine reacts with HNO3 as follows:

C2H5NH2 + HNO3 → C2H5NH3⁺ + NO3⁻

To solve this question we need to find the moles of ethyl amine and the moles of HNO3:

<em>Moles C2H5NH2:</em>

0.0500L * (0.100mol/L) = 0.00500 moles ethyl amine

<em>Moles HNO3:</em>

0.201L * (0.025mol/L) = 0.005025 moles HNO3

That means HNO3 is in excess. The moles in excess are:

0.005025 moles HNO3 - 0.00500 moles ethyl amine =

2.5x10⁻⁵ moles HNO₃

In 50 + 201mL = 251mL = 0.251L:

2.5x10⁻⁵ moles HNO₃ / 0.251L = 9.96x10⁻⁵M = [H+]

As pH = -log [H+]

pH = -log 9.96x10⁻⁵M

pH = 4.00 is the pH of the mixture

6 0

2 years ago

A sample of gas is observed to effuse through a pourous barrier in 4.98 minutes. Under the same conditions, the same number of m

kogti [31]

Answer:

The molar mass of the unknown gas is $\mathbf{ 51.865 \ g/mol}$

Explanation:

Let assume that the gas is O2 gas

O2 gas is to effuse through a porous barrier in time t₁ = 4.98 minutes.

Under the same conditions;

the same number of moles of an unknown gas requires time t₂ = 6.34 minutes to effuse through the same barrier.

From Graham's Law of Diffusion;

Graham's Law of Diffusion states that, at a constant temperature and pressure; the rate of diffusion of a gas is inversely proportional to the square root of its density.

i.e

$R \ \alpha \ \dfrac{1}{\sqrt{d}}$

$R = \dfrac{k}{d}$ where K = constant

If we compare the rate o diffusion of two gases;

$\dfrac{R_1}{R_2}= {\sqrt{\dfrac{d_2}{d_1}}$

Since the density of a gas d is proportional to its relative molecular mass M. Then;

$\dfrac{R_1}{R_2}= {\sqrt{\dfrac{M_2}{M_1}}$

Rate is the reciprocal of time ; i.e

$R = \dfrac{1}{t}$

Thus; replacing the value of R into the above previous equation;we have:

$\dfrac{R_1}{R_2}={\dfrac{t_2}{t_1}}$

We can equally say:

${\dfrac{t_2}{t_1}}= {\sqrt{\dfrac{M_2}{M_1}}$

${\dfrac{6.34}{4.98}}= {\sqrt{\dfrac{M_2}{32}}$

$M_2 = 32 \times ( \dfrac{6.34}{4.98})^2$

$M_2 = 32 \times ( 1.273092369)^2$

$M_2 = 32 \times 1.62076418$

$\mathbf{M_2 = 51.865 \ g/mol}$

7 0

2 years ago

Comppare and contrast sexual reproucton and asexual repructon

JulsSmile [24]

Answer:

Asexual reproduction involves only 1 parent. The daughter cells / offspring are the exact clones of the parent. There’s no variety. The end products are only 2 daughter cells. Sexual reproduction involves 2 parents (a mate). The offspring consists of a mixture of genes from both parents. There’s more variety to the offspring. 4 daughter cells are produced in sexual reproduction. Both undergo cell division. Asexual reproduction = mitosis Sexual reproduction = meiosis. Sexual reproduction produces the gametes, asexual produces body cells

Explanation:

7 0

2 years ago