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Andrei [34K]
3 years ago
5

Study the diagram and answer these questions:

Chemistry
2 answers:
Oxana [17]3 years ago
7 0
2 electrons in the n=1 orbit
6 electrons in its n=2 orbit
8 protons in nucleus
8 electrons
6 electrons
4 electrons shared
Covalent bond exist between the two oxygen atoms
Stolb23 [73]3 years ago
5 0

Explanation:

The n = 1 means the first shell of an atom whereas n = 2 means the second shell of an atom and so on.

As every atom consists of three sub-atomic particles which are protons, neutrons and electrons.

Protons and neutrons reside inside the nucleus of an atom and electrons revolve outside the nucleus of the atom.

A covalent bond is defined as the bond formed by sharing of electrons between the two combining atoms.

Therefore, the given questions are answered as follows.

  • There are 2 electrons in the n = 1 orbit of each atom.
  • Each atom has 8 electrons in its n = 2 orbit, after the sharing of electrons take place between both the oxygen atoms.
  • Each atom has 8 protons in its nucleus.
  • Each atom has 8 total electrons.
  • There are 6 electrons in oxygen's outer shell before sharing electrons.
  • There are 4 electrons being shared between the two atoms.
  • Double bonds exist between the two oxygen atoms. This is because sharing of two electrons is taking place. Hence, a double covalent bond exists when two oxygen atoms when they chemically combine together.
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Methane gas and chlorine gas react to form hydrogen chloride gas and carbon tetrachloride gas. What volume of hydrogen chloride
IrinaK [193]

The question is incomplete, here is the complete question:

Methane gas and chlorine gas react to form hydrogen chloride gas and carbon tetrachloride gas. What volume of hydrogen chloride would be produced by this reaction if 1.1 mL of methane were consumed? Be sure your answer has the correct number of significant digits.

<u>Answer:</u> The volume of hydrogen chloride produced in the reaction will be 4.4 mL

<u>Explanation:</u>

We are given:

Volume of methane gas = 1.1 mL

The chemical equation for the reaction of methane gas and chlorine gas follows:

CH_4(g)+4Cl_2(g)\rightarrow 4HCl(g)+CCl_4(g)

Moles of methane gas = 1 mole

Moles of hydrogen chloride gas = 4 moles

The relationship of number of moles and volume at constant temperature and pressure was given by Avogadro's law. This law states that volume is directly proportional to number of moles at constant temperature and pressure.

The equation used to calculate number of moles is given by:

\frac{V_1}{n_1}=\frac{V_2}{n_2}

where,

V_1\text{ and }n_1 are the volume and number of moles of methane gas

V_2\text{ and }n_2 are the volume and number of moles of hydrogen chloride

We are given:

V_1=1.1mL\\n_1=1mol\\V_2=?L\\n_2=4mol

Putting values in above equation, we get:

\frac{1.1}{1}=\frac{V_2}{4}\\\\V_2=\frac{1.1\times 4}{1}=4.4mL

Hence, the volume of hydrogen chloride produced in the reaction will be 4.4 mL

5 0
3 years ago
In a study of the following reaction at 1200 K it was observed that when the equilibrium partial pressure of water vapor is 15.0
sp2606 [1]

Answer:

The value of K_p for this reaction at 1200 K is 4.066.

Explanation:

Partial pressure of water vapor at equilibrium = p^o_{H_2O}=15.0 Torr

Partial pressure of hydrogen gas at equilibrium = p^o_{H_2}=?

Total pressure of the system at equilibrium P = 36.3 Torr

Applying Dalton's law of partial pressure to determine the partial pressure of hydrogen gas at equilibrium:

P=p^o_{H_2O}+p^o_{H_2}

p^o_{H_2}=P-p^o_{H_2O}=36.3 Torr- 15.0 Torr = 21.3 Torr

3 Fe(s) 4 H_2O(g)\rightleftharpoons Fe_3O_4(s) 4 H_2(g)

The expression of K_p is given by:

K_p=\frac{(p^o_{H_2})^4}{(p^o_{H_2O})^4}

K_p=\frac{(21.3 Torr)^4}{(15.0 Torr)^4}=4.066

The value of K_p for this reaction at 1200 K is 4.066.

6 0
3 years ago
Question 1 (1 point) Which of the following summarizes cellular respiration?
salantis [7]

Answer:

oxygen reacts with glucose to produce carbon dixiode into water and release energy. It is 1

Explanation:

3 0
2 years ago
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How many grams of hydrogen gas get produced if 10 g of aluminum reacts?
Degger [83]

Answer:

9.8

Explanation:

8 0
3 years ago
Determine how many atoms of pure silver will be created when 19.83 x 1023 atoms of copper are used in the following reaction:
Lubov Fominskaja [6]

Answer:

\boxed{3.966 \times 10^{24}\text{ atoms of Ag}}

Explanation:

(a) Balanced equation

Cu + 2AgNO₃ ⟶ Cu(NO₃)₂+ 2Ag

(b) Calculation

You want to convert atoms of Cu to atoms of Ag.

The atomic ratio is ratio is 2 atoms Ag:1 atom Cu

\text{Atoms of Ag} = 19.83 \times 10^{23}\text{atoms Cu} \times \dfrac{\text{2 atoms Ag}}{\text{1 atom Cu}}\\\\= 3.966 \times 10^{24}\text{ atoms of Ag}\\\\\text{The reaction will produce }\boxed{\mathbf{3.966 \times 10^{24}}\textbf{ atoms of Ag}}

4 0
3 years ago
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