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Andrei [34K]
3 years ago
5

Study the diagram and answer these questions:

Chemistry
2 answers:
Oxana [17]3 years ago
7 0
2 electrons in the n=1 orbit
6 electrons in its n=2 orbit
8 protons in nucleus
8 electrons
6 electrons
4 electrons shared
Covalent bond exist between the two oxygen atoms
Stolb23 [73]3 years ago
5 0

Explanation:

The n = 1 means the first shell of an atom whereas n = 2 means the second shell of an atom and so on.

As every atom consists of three sub-atomic particles which are protons, neutrons and electrons.

Protons and neutrons reside inside the nucleus of an atom and electrons revolve outside the nucleus of the atom.

A covalent bond is defined as the bond formed by sharing of electrons between the two combining atoms.

Therefore, the given questions are answered as follows.

  • There are 2 electrons in the n = 1 orbit of each atom.
  • Each atom has 8 electrons in its n = 2 orbit, after the sharing of electrons take place between both the oxygen atoms.
  • Each atom has 8 protons in its nucleus.
  • Each atom has 8 total electrons.
  • There are 6 electrons in oxygen's outer shell before sharing electrons.
  • There are 4 electrons being shared between the two atoms.
  • Double bonds exist between the two oxygen atoms. This is because sharing of two electrons is taking place. Hence, a double covalent bond exists when two oxygen atoms when they chemically combine together.
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Hello, everyone!
marusya05 [52]

Answer: 27.09 ppm and 0.003 %.

First, <u>for air pollutants, ppm refers to parts of steam or gas per million parts of contaminated air, which can be expressed as cm³ / m³. </u>Therefore, we must find the volume of CO that represents 35 mg of this gas at a temperature of -30 ° C and a pressure of 0.92 atm.

Note: we consider 35 mg since this is the acceptable hourly average concentration of CO per cubic meter m³ of contaminated air established in the "National Ambient Air Quality Objectives". The volume of these 35 mg of gas will change according to the atmospheric conditions in which they are.

So, according to the <em>law of ideal gases,</em>  

PV = nRT

where P, V, n and T are the pressure, volume, moles and temperature of the gas in question while R is the constant gas (0.082057 atm L / mol K)

The moles of CO will be,

n = 35 mg x \frac{1 g}{1000 mg} x \frac{1 mol}{28.01 g}

→ n = 0.00125 mol

We clear V from the equation and substitute P = 0.92 atm and

T = -30 ° C + 273.15 K = 243.15 K

V =  \frac{0.00125 mol x 0.082057 \frac{atm L}{mol K}  x 243 K}{0.92 atm}

→ V = 0.0271 L

As 1000 cm³ = 1 L then,

V = 0.0271 L x \frac{1000 cm^{3} }{1 L} = 27.09 cm³

<u>Then the acceptable concentration </u><u>c</u><u> of CO in ppm is,</u>

c = 27 cm³ / m³ = 27 ppm

<u>To express this concentration in percent by volume </u>we must consider that 1 000 000 cm³ = 1 m³ to convert 27.09 cm³ in m³ and multiply the result by 100%:

c = 27.09 \frac{cm^{3} }{m^{3} } x \frac{1 m^{3} }{1 000 000 cm^{3} } x 100%

c = 0.003 %

So, <u>the acceptable concentration of CO if the temperature is -30 °C and pressure is 0.92 atm in ppm and as a percent by volume is </u>27.09 ppm and 0.003 %.

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How many grams of CO2 could be formed with 2.09 x 1023 atoms of O?
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Answer:

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Explanation:

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