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Ksivusya [100]
3 years ago
15

A sled sliding on a flat,icy surface with a constant velocity is best described by

Physics
1 answer:
AysviL [449]3 years ago
5 0
The first one is actually Newton's First Law of Motion. 

Newton's First Law of Motion is commonly stated as "an object in motion will remain in motion unless acted upon by an outside force." This sled is moving across the ice at the same constant speed and velocity meaning it will won't stop unless an outside force acts upon it. An example being someone coming and grabbing the sled or maybe the sled slips off of the ice and finds itself stuck in a pile of snow. Similarly, if the sled was not moving, it would not move unless acted upon again by an outside force. 

You believed it to be Newton's Third Law, but for future reference, his third law is more about every action having an equal opposite reaction. This wouldn't explain what is currently happening with the sled. A helpful tip into figuring out where to start in figuring out the answer I got is in the example you gave it literally states "with a constant velocity" which also ends up being in the description of Newton's First Law. Though, don't rely on that because the answer could have had a made up definition.

Unfortunately, I do not know the answer to your other question. I apologize. Hope this helped.
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A steel ball and a wooden ball of the same diameter are released together from the top of a tower. In the absence of air resista
ella [17]

Answer:

False

Explanation:

The steel ball and the wooden ball do not have the same force acting on them because their masses are different. But, they have the same acceleration which is the acceleration due to gravity g = 9.8 m/s².

Using the equation of motion under freefall, s = ut +1/2gt². Since u = 0,

s = 1/2gt² ⇒ t = √(2s/g)

Since. s = height is the same for both objects, they land at the same time neglecting air resistance.

8 0
3 years ago
For a sound coming from a point source, the amplitude of the sound is inversely
gayaneshka [121]

Answer ) Sound level equation

The intensity of a sound wave is related to its amplitude squared by the following relationship: I=(Δp)22ρvw I = ( Δ p ) 2 2 ρ v w . Here Δp is the pressure variation or pressure amplitude (half the difference between the maximum and minimum pressure in the sound wave) in units of pascals (Pa) or N/m2.

4 0
2 years ago
An inattentive driver is traveling 18.0 m/s when he notices a red light ahead. his car is capable of decelerating at a rate of 3
ryzh [129]

Speed of the car given initially

v = 18 m/s

deceleration of the car after applying brakes will be

a = 3.35 m/s^2

Reaction time of the driver = 0.200 s

Now when he see the red light distance covered by the till he start pressing the brakes

d_1 = v* t

d_1 = 18* 0.200 = 3.6 m

Now after applying brakes the distance covered by the car before it stops is given by kinematics equation

v_f^2 - v_i^2 = 2 a s

here

vi = 18 m/s

vf = 0

a = - 3.35

so now we will have

0^2 - 18^2 = 2*(-3.35)(s)

s = 48.35 m

So total distance after which car will stop is

d = d_1 + d_2

d = 48.35 + 3.6 = 51.95 m

So car will not stop before the intersection as it is at distance 20 m

3 0
3 years ago
Why are some substances dissolve both polar and nonpolar substances?
dlinn [17]

Answer:

Because water is polar and oil is nonpolar, their molecules are not attracted to each other.<em> polar solvents dissolve polar solutes, and nonpolar solvents dissolve nonpolar solutes.</em>

<em></em>

<em></em>

<em>please mark me as the brainliest :) </em>

<em></em>

<em>use your brain :)</em>

8 0
3 years ago
What are the factors that effect the strength of a frictional force???
seropon [69]

If you write down the formula for friction, you will get an answer.

Ff = u * N               Where N is a push down force that an object experiences.

                              u (mu) is a constant and has no units

It may not be accelerating and still experience friction. A is not correct.

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Buoyant forces are a different thing altogether. Generally friction has nothing to do with them. C is incorrect.

The last one is your answer. Technically mg should be the answer and not mass, but the second part is correct.

5 0
2 years ago
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