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3 years ago

What might cause convection currents in a hot spring?

Physics

1 answer:

Aleks [24]3 years ago

7 0

Answer and explanation;

-The cause of convention currents in a hot spring is rainwater and melted snow is cool and denser and sinks to the bottom of the hot spring where it is heated by a shallow magma chamber. The heated water expands and is less dense and rises to the top.

Explanation;

-Convention Current is the movement of fluid caused by the differences in temperature. Transference of heat from one part of a fluid to another.

-Lighter (less dense), warm material rises while heavier (more dense) cool material sinks. It is this movement that creates circulation patterns known as convection currents in the atmosphere, in water, and in the mantle of Earth. In the atmosphere, as air warms it rises, allowing cooler air to flow in underneath.

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10.

nlexa [21]

Answer:

Cell Membrane

Explanation:

The cell membrane controls what goes in and out of a cell, and keeps it shape, much like a city limit.

3 0

3 years ago

How much heat must be removed from 200 pounds of blanched vegetables at 189 degrees F to freeze them to a temperature of 22 degr

Virty [35]

To solve this problem it is necessary to apply the concepts related to heat exchange in the vegetable and water.

By definition the exchange of heat is given by

$Q =mc\Delta T$

where,

m = mass

c = specific heat

$\Delta T$ = Change in temperature

Therefore the total heat exchange is given as

$\Delta Q = Q_w+Q_v$

$\Delta Q = m_wc_w(T_i-T_f)+m_vc_v(T_i-T_f)$

Our values are given as,

Total mass is $M_T$ = 200lb ,however the mass of solid vegetable and water is given as,

$m_v= 0.4*200lb = 80lb$

$m_w=0.6*200lb=120lb$

$T_i = 183\°F\\T_f = 22\°F\\c_w = 1Btu/lbF\\c_v = 0.24Btu/lbF$

Replacing at our equation we have,

$\Delta Q = m_wc_w(T_i-T_f)+m_vc_v(T_i-T_f)$

$\Delta Q = (120)(1)(183-22)+(80)(0.24)(183-22)$

$\Delta Q = 22411.2Btu$

Therefore the heat removed is 22411.2 Btu

6 0

3 years ago

An object is at rest when it undergoes a constant acceleration of 13 m/s ^ 2 for 5.0 seconds. How far will it have traveled duri

Orlov [11]

Answer:

162.5 m is the distance traveled by an object.

Explanation:

Given that,

An object's constant acceleration (a) is $13m/s^2$ .

The time (t) it traveled is 5 seconds.

The object is at rest that is "initial velocity" (u) is 0 m/s.

To find the distance traveled use the below formula,

$s=ut+\frac{1}{2}at^2$

Where, "s" is distance traveled, "u" is initial velocity, "a" is acceleration and "t" is time taken.

Substitute the given values in the above formula,

$s=0\times5+\frac{1}{2}\times13\times 5^2$

$s=0+\frac{1}{2}\times13\times 25$

$s=0+\frac{1}{2}\times325$

s = 162.5 m

Therefore, distance traveled is 162.5 m.

3 0

3 years ago

A positively charged object is placed to the left of a negatively charged object. Which best describes how the positively charge

Helga [31]

Explanation:

As per the law of electrostatics, two positive or negative charge repel each other while two opposite charge attract each other.
In this case, a positively charged object is placed to the left of a negatively charged object. It would mean that the positive charge move in the direction of negative charge, so as to attract each other.
Hence, the positively charged object will move to the right.

8 0

3 years ago

What is the regular rising and falling of ocean water due to the gravitational pull of the sun and moon?

Tpy6a [65]

The tide? Low tide and High tide?

8 0

3 years ago