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Arturiano [62]
3 years ago
14

A skater glides along a circular path of radius 3.00 m. If he coasts around one half of the circle, find the magnitude of the di

splacement vector. 6.00 m (in m)
Physics
1 answer:
aleksandrvk [35]3 years ago
7 0

Answer:

The magnitude of the displacement is 6.00 m.

Explanation:

Given that,

Radius = 3.00 m

Displacement :

The displacement is the shortest distance between initial and final points,

We need to calculate the magnitude of the displacement

Using formula of displacement

d=2r

Put the value into the formula

d=2\times3.00

d=6.00\ m

Hence, The magnitude of the displacement is 6.00 m.

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Answer:

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Explanation:

L = 100 m

A = 1 mm^2 = 1 x 10^-6 m^2

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Let the cable stretch be ΔL.

By the formula of Young's modulus

Y=\frac{F\times L}{A\times\Delta L}

\Delta L=\frac{F\times L}{A\times\Y}

\Delta L=\frac{1000\times 100}{10^{-6}\times10^{11}}

ΔL = 1 m

Thus, the cable stretches by 1 m.

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