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Evgen [1.6K]
3 years ago
5

Outside a spherically symmetric charge distribution of net charge Q, Gauss's law can be used to show that the electric field at

a given distance:___________.
A) must be directed inward.
B) acts like it originated in a point charge Q at the center of the distribution.
C) must be directed outward.
D) must be greater than zero.
E) must be zero.
Physics
1 answer:
Sergio039 [100]3 years ago
3 0

Answer:

Q at the center of the distribution.

Explanation:

  • The Gauss's law is the law that relates to the distribution of electrical charges to the resulting electrical field. It states that a flux of electricity outside the arabatory closed surface is proportional to the electricitical harg enclosed by the surface.
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3 years ago
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an object was accelerated with a force of 150 N from rest to a velocity of 10m/s in 5 sec. the force of friction opposing the ob
astra-53 [7]

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Mass  =  (force) / (acceleration)

There was 150N of force in one direction and 100N of 'force' in
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Acceleration = (change in speed) / (time for the change)
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7 0
3 years ago
How many times bigger is the earth than the moon?
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7 0
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Helppp plss
shutvik [7]

Answer:

a) P = 149140[w]; b) 1491400[J]; c) v = 63.06[m/s]

Explanation:

As the solution to the problem indicates, we must convert the power unit from horsepower to kilowatts.

P = 200 [hp]

200[hp] * 745.7 [\frac{watt}{1 hp}]\\149140[watt]

Now the power definition is known as the amount of work done in a given time

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We have the time, and the power therefore we can calculate the work done.

w = P * t

w = 149140 * 10 = 1491400 [J]

And finally, we can calculate the velocity using, the expression for kinetic energy

E_{k}=w=0.5*m*v^{2}\\  where:\\v = velocity[m/s]\\m=mass=750[kg]\\w=work=1491400[J]\\

The key to solving this problem is to recognize that work equals kinetic energy

v=\sqrt{\frac{w}{0.5*m}}  \\v=\sqrt{\frac{1491400}{0.5*750}}  \\v=63.06[m/s]

3 0
3 years ago
Line segment gj is a diameter of circle l. angle k measures (4x 6)°. circle l is inscribed with triangle g j k. line segment g j
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8 0
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