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3 years ago

HELP ASAP

1 answer:

6 0

I would think it would be because 1- it would be hard to change all the measurements on different sites.
2- everyone in the U.S is used to this system so it would be stupid to change.
3- it would be hard to learn a new system.

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!!!!!

dalvyx [7]

Answer:

46 m at 9.5 degrees east of south

Explanation:

5 0

3 years ago

Jared has a nut sack that weighs 14 ounces when weighed. If Becky puts an amount of force on them, x , what is the equation that

topjm [15]

X+14 bc that’s what it will equal.

6 0

3 years ago

The following equation is an example of decay? 232/90 TH---4/2 HE +228/88 RA?

DaniilM [7]

Answer:

Alpha decay

Explanation:

Alpha decay is one of the three major types of decays, others being, beta decay and gamma decay.
When a radioactive isotope undergoes alpha decay it emits alpha particles. An alpha particle is equivalent to the nucleus of Helium atom.
Therefore, an atom undergoing decay, its atomic mass is decreased by 4 and its atomic number is decreased by 2.
Thus, since 232/90 Th, has undergone alpha decay its mass number is reduced by 4 to 228 and its atomic number by 2 to 88, and becomes 228/88 Ra.

5 0

3 years ago

Which of the following is NOT an advantage of using a wheel and axle?

kakasveta [241]

Answer:

the first one

Explanation:

4 0

3 years ago

An electron is a negatively charged particle that has a charge of magnitude, e - 1.60 x 10-19 C. Which one of the following stat

Ivahew [28]

Answer:

The electric field is directed toward the electron and has a magnitude of $E=\frac{ke}{r^{2} }$ .

Explanation:

An electric field is define as the surrounding of charges which exert a force on each other and this force can be attractive or repulsive depends on the charge.

In the given case electron is given and the magnitude of charge on electron is $e=1.6\times 10^{-19}C$

Electric field can be represented as,

$E=\frac{kQ}{r^{2} }$

Here, r is the distance between the point ande charge, k is the electric field constant and Q is the charge.

In the given question an electron is given so electric field will be,

$E=\frac{ke}{r^{2} }$

As we know that electric field start from the positive charge and vanish in the negative charge.

So, here the electric field will be $E=\frac{ke}{r^{2} }$ and it is directed toward the electron because of negative charge on the electron.

6 0

3 years ago

HELP ASAP﻿

HELP ASAP