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2 years ago

13

Why does the chemical reaction seen here obey the law of conservation of matter?

2 answers:

sdas [7]2 years ago

8 0

The chemical reaction seen here obey the law of conservation of matter because there are the same number of atoms of each element shown on both sides. The answer is A. Thank you for posting your question here. I hope it helps.

ss7ja [257]2 years ago

7 0

Why does the chemical reaction seen here obey the law of conservation of matter?

<u><em>Answer:</em></u>

Because there are the same number of atoms of each element shown on both sides

<u><em>Explanation</em></u>

As in chemical reactions, atoms bonds are break and new bonds are formed. As new substance are formed but overall they have same elements, no new elements come from outside or go to outside. In other words , rearrangement of atoms take place but number of atoms remained same.

NaOH + HCl -----> NaCl + H2O

As in above reaction there are the same number of atoms of each element shown on both sides .

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2 years ago

Why is electrolysis used not carbon to extract metal

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2 years ago

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inn [45]

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2 years ago

Calculate the standard reaction enthalpy for the reaction NO2(g) → NO(g) + O(g) given +142.7 kJ/mol for the standard enthalpy of

bulgar [2K]

Answer:

The standard reaction enthalpy for the given reaction is 235.15 kJ/mol.

Explanation:

$O_2(g) \rightarrow \frac{2}{3}O_3(g),\Delta H^o_{1}=142.7 kJ/mol$ ..[1]

$O_2(g) \rightarrow 2 O(g),\Delta H^o_{2}=498.4 kJ/mol$ ..[2]

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$NO_2(g)\rightarrow NO(g) + O(g),\Delta H^o_{4}=?$ ..[4]

Using Hess's law:

Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.

2 × [4] = [2]- (3 ) × [1] - (2) × [3]

$2\times \Delta H^o_{4}=\Delta H^o_{2} -3\times \Delta H^o_{1}-2\times \Delta H^o_{3}$

$2\times \Delta H^o_{4}=498.4 kJ/mol-3\times 142.7 kJ/mol-2\times -200 kJ/mol$

$2\times \Delta H^o_{4}=470.3 kJ/mol$

$\Delta H^o_{4}=\frac{470.3 kJ/mol}{2}=235.15 kJ/mol$

The standard reaction enthalpy for the given reaction is 235.15 kJ/mol.

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