Answer:

Explanation:
- First rearrange the whole equation by keeping t in one side and rest parameters in another side of equation
- Then plug-in all the given values for each parameters and get the solution

or, 
Now plug-in all given values:

So, 
The molecular formula is D. C_8H_20O_4Si.
<em>Step 1</em>.Calculate the <em>empirical formula
</em>
a) Calculate the moles of each element
Moles of C= 196.01 g C × (1 mol C/12.01 g C) = 16.325 mol C
Moles of H = 41.14 g H × (1 mol H/1.008 g H) = 40.813 mol H
Moles of O = 130.56 g O × (1 mol O/16.00 g O) = 8.1650 mol O
Moles of Si = 57.29 g Si × (1 mol Si/28.085 g Si) = 2.0399 mol Si
b) Calculate the molar ratio of each element
Divide each number by the smallest number of moles and round off to an integer
C:H:O:Si = 8.0027:20.008:4.0027:1 ≈ 8:20:4:1
c) Write the empirical formula
EF = C_8H_20O_4Si
<em>Step </em>2. Calculate the <em>molecular formula</em>
EF Mass = 208.33 u
MF mass = 208.329 u
MF = (EF)_n
n = MF Mass/EF Mass = 208.329 u/208.33 u = 1.0000 ≈ 1
MF = C_8H_20O_4Si
Answer:
c. 131 kPa
Explanation:
Hello!
In this case, since the relationship between volume and pressure is inversely proportional, based on the Boyle's law:

Considering that the standard pressure is 101.325 kPa, we can compute the final pressure as shown below:

Therefore, the answer is c. 131 kPa
.
Best regards!!
Answer:
The answer is
<h2>1.38 g/mL</h2>
Explanation:
The density of a substance can be found by using the formula

From the question
mass of liquid = 138 g
volume = 100 mL
The density of the liquid is

We have the final answer as
<h3>1.38 g/mL</h3>
Hope this helps you