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EastWind [94]
3 years ago
10

A line passes through the points R(-1,-5) and S(-3,-1). Write the equation of the line through the point A(4,0) that is parallel

to line RS.
y= -2x-2
y= -2x+8
y= 2x-8
y= 2x

Mathematics
1 answer:
IRISSAK [1]3 years ago
4 0
Sorry I was moving around taking the picture and my handwriting is sloppy. But I hope you understand how I got the answer

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If fixed costs are $561,000 and the unit contribution margin is $8.00, what is the break-even point in units if variable costs a
olga nikolaevna [1]
The break even point is the point where in the total cost and the total revenue of the business are of the same value which means there is no profit or no loss. It is would be the minimum point that a business to reach in order to be able to recover the costs without any loss. At this point selling cost is equal to the sum of the fixed cost and the variable cost. To determine the break even point in units, we do as follows:

SC = FC + VC
Px = FC + Vx
where x is the number of units, P is the price per unit and V is the variable cost per unit.

x = FC / P - V
x = 561000 / (8.00 - 0.50)
x = 74800 units
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Vince added 0.912,0.882 ,and 1.354 liters of liquid to a bottle.About how much is in the bottle?
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3.148 liters of liquid. 
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3 years ago
A population of 1200 leopards decreases by 12% per year. How many leopards will there be in the population after 6 years? Round
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3 0
3 years ago
Principle = 30,000<br>Time = 4 years<br>Rate = 30<br>Then find the simple interest ?​
Nutka1998 [239]

Answer:

\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline\color{brown}{Given:}}}}}}\end{gathered}

  • {\dashrightarrow \sf{Principle = Rs.30000}}
  • {\dashrightarrow \sf {Time = 4 \: years}}
  • \dashrightarrow \sf{Rate = 30\%}
  • \begin{gathered}\end{gathered}

\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline\color{brown}{To Find:}}}}}}\end{gathered}

  • \dashrightarrow{\sf{Simple \: Interest }}

\begin{gathered}\end{gathered}

\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline\color{brown}{Using Formula:}}}}}}\end{gathered}

\dag{\underline{\boxed{\sf{ S.I = \dfrac{P \times R \times T}{100}}}}}

Where

  • \dashrightarrow{\sf{S.I = Simple \:  Interest }}
  • {\dashrightarrow{\sf{P = Principle }}}
  • {\dashrightarrow{\sf{ R = Rate }}}
  • {\dashrightarrow{\sf{T = Time}}}

\begin{gathered}\end{gathered}

\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline\color{brown}{Solution:}}}}}}\end{gathered}

{\quad {: \implies{\sf{ S.I =  \bf{\dfrac{P \times R \times T}{100}}}}}}

Substituting the values

{\quad {: \implies{\sf{ S.I =  \bf{\dfrac{30000 \times 30\times 4}{100}}}}}}

{\quad {: \implies{\sf{ S.I =  \bf{\dfrac{30000 \times 120}{100}}}}}}

{\quad {: \implies{\sf{ S.I =  \bf{\dfrac{3600000}{100}}}}}}

{\quad {: \implies{\sf{ S.I =  \bf{\cancel{\dfrac{3600000}{100}}}}}}}

{\quad {: \implies{\sf{ S.I =  \bf{Rs.36000}}}}}

{\dag{\underline{\boxed{\sf{ S.I ={Rs.36000}}}}}}

  • Henceforth,The Simple Interest is Rs.36000..

\begin{gathered}\end{gathered}

\begin{gathered}{\Large{\textsf{\textbf{\underline{\underline\color{brown}{Learn More:}}}}}}\end{gathered}

\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered} \dag \: \underline{\bf{More \: Useful \: Formula}}\\ {\boxed{\begin{array}{cc}\dashrightarrow {\sf{Amount = Principle + Interest}} \\ \\ \dashrightarrow \sf{ P=Amount - Interest }\\ \\ \dashrightarrow \sf{ S.I = \dfrac{P \times R \times T}{100}} \\ \\ \dashrightarrow \sf{P = \dfrac{Interest \times 100 }{Time \times Rate}} \\ \\ \dashrightarrow \sf{P = \dfrac{Amount\times 100 }{100 + (Time \times Rate)}} \\ \end{array}}}\end{gathered}\end{gathered}\end{gathered}\end{gathered}\end{gathered}

8 0
3 years ago
Read 2 more answers
Y = -x^2<br><br>Answer the problem.​
Vinil7 [7]

Answer:

x=0

Step-by-step explanation:

substitute y=0

0= -x^2

then swap the sides

-x^2=0 ,

change the signs

x^2=0

set the base equal to 0

x=0

8 0
3 years ago
Read 2 more answers
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