Answer:
Na₁₁ = 1s² 2s² 2p⁶ 3s¹
Explanation:
Sodium is present in group 1.
It is alkali metal.
It has one valence electron.
The atomic number of sodium is 11.
Its atomic mass is 23 amu.
The longhand notation of electronic configuration of sodium can be written as,
Na₁₁ = 1s² 2s² 2p⁶ 3s¹
The electronic configuration in shorthand notation( noble gas) would be written as,
Na₁₁ = [Ne] 3s¹
Sodium loses its one valence electron to complete the octet and get stable thus form +1 cation.
It react with halogen and form salt. Such as sodium chloride.
2Na + Cl₂ → 2NaCl
1 mol of CO2 is 44.01g/mol
So multiply that by 2 to get 2 mol of CO2, which is 88.02g
Answer:
P₂ = 3.86 atm .
Explanation:
We assume that during this change , the temperature of the gas remains constant .
So the gas will obey Boyle's law .
P₁ V₁ = P₂V₂
5.08 x 7.56 = P₂ x 9.94
P₂ = 3.86 atm .
Answer:
C3H6
Explanation:
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The Options are as follow,
<span>a.
it has 13 protons c. it has 13 neutrons </span>
<span>b.
it has 13 electrons d. it
has 7 neutrons</span>
Answer:
Option-d is the correct answer.
Explanation:
As we know that C-13 has a atomic mass of 13. Also, atomic mass is given as,
<span> Atomic Mass = # of Protons + # of Neutrons --- (1)</span>
Since;
Atomic Mass = 13
And,
# of protons = 6 (as number of protons = atomic number)
Putting values in equation 1,
13 = 6 - # of Neutrons
Solving for Number of Neutrons,
# of Neutrons = 13 - 6
# of Neutrons = 7
