Answer:
Step-by-step explanation:
Alright, lets get started.
Suppose they take t minutes to meet each other.
Distance covered by first friend in t minutes, = 0.2 *t=0.2∗t
Distance covered by second friend in t minutes , =0.15 *t=0.15∗t
Total distance is given as 7, so
0.2 t + 0.15 t = 70.2t+0.15t=7
0.35 t = 70.35t=7
t = 20t=20
means after 20minutes they will meet.
SO. the average speed is 10m: Answer
Answer:
-191.7°C
Explanation:
P . V = n . R . T
That's the Ideal Gases Law. It can be useful to solve the question.
We replace data:
2.5 atm . 8 L = 3 mol . 0.082 L.atm/mol.K . T°
(2.5 atm . 8 L) / (3 mol . 0.082 L.atm/mol.K) = T°
T° = 81.3 K
We convert T° from K to C°
81.3K - 273 = -191.7°C
Answer:
16.6 g of Al are produced in the reaction of 82.4 g of AlCl₃
Explanation:
Let's see the decomposition reaction:
2AlCl₃ → 2Al + 3Cl₂
2 moles of aluminum chloride decompose to 2 moles of solid Al and 3 moles of chlorine gas.
We determine the moles of salt:
82.4 g . 1mol/ 133.34g = 0.618 moles
Ratio is 2:2. 2 moles of salt, can produce 2 moles of Al
Then, 0.618 moles of salt must produce 0.618 moles of Al.
Let's convert the moles to mass → 0.618 mol . 26.98g /mol = 16.6 g
The bond order of Mg2 molecule is given by:
Mg2 = 4e⁻= 3σs(2e⁻) 3σs*(2e⁻) 3σp(0) 3πp(0e⁻) 3πp*(0e⁻)
3σp*(0e⁻)
Bond Order = ½[Σ (bonding e-) - Σ (antibonding e-)]
bo = ½[ {σs(2e⁻)} - {σs*(2e⁻)}] = 0
the bond between Mg2 molecules are ionic bonding and it
stable.
