Formula for the depression in freezing point is:
-(1)
where is depression in freezing point,
is Van't Hoff factor,
is molal freezing point depression constant, and
is molality of the solution.
Molality of the solution, (given)
Molal freezing point depression constant of water,
Depression in freezing point of solution,
Substituting the values in equation (1):
Hence, the Van't Hoff factor (i) for is 1.412.
Answer:
Molarity = 0.24 M
Explanation:
Given data:
Number of moles of Mg(NO₃)₂ = 0.181 mol
Volume of solution = 0.750 L
Molarity of solution = ?
Solution:
Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.
Formula:
Molarity = number of moles of solute / L of solution
by putting values,
Molarity = 0.181 mol / 0.750 L
Molarity = 0.24 M
Answer:
950mL
Explanation:
The following were Data were obtained from the question:
Initial volume (V1) = 100mL
Initial pressure (P1) = stp = 760mmHg
Final pressure (P2) = 80mmHg
Final volume (V2) =..?
The final volume of the gas can be obtained by using the Boyle's law equation as follow:
P1V1 = P2V2
760 x 100 = 80 x V2
Divide both side by 80
V2 = (760 x 100) /80
V2 = 950mL
Therefore, the new volume of the gas is 950mL
Answer:
0.08moles
Explanation:
Given parameters:
Volume of gas = 0.5L
Pressure of gas = 400kPa
Temperature of gas = 300K
Unknown:
Number of moles of N₂ = ?
Solution:
Applying the ideal gas law which is a combination of the three gas law: Boyle's law, Charles's law and Avogadro's law will solve this problem.
The ideal gas law is stated as;
PV = nRT
P is the pressure of the gas
V is the volume of the gas
n is the number of moles
R is the gas constant
T is the temperature of the gas
We need to convert kPa of the pressure to atm which is a more comfortable unit to work with.
400kPa will be = 3.95atm
Input the variables in the equation;
3.95 x 0.5 = n x 0.082 x 300
n = 0.08moles