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Ira Lisetskai [31]
3 years ago
5

Please help! I’m begging youuuuuuuuuuuuuuu

Chemistry
1 answer:
VMariaS [17]3 years ago
7 0
Florine and Neon both have 10 neutrons
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When 45.8 g of K2CO3 react with excess HCI, 46.3 g of KCl are formed. Calculate the theoretical and % yields of
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Theoretical yield = 49.45g

Percentage yield= 93.6%

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HELP QUICK ILL GIVE YOU BRAINLIEST AND 25 POINTS! bromine (br) has four energy levels. name 2 other elements that would have fou
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titanium and potassium

Explanation:

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The _______ are found on the left side of the arrow in a chemical reaction.
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The reactants are found on the left side, the products are found on the right side.
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A gas has a volume of 5.00 L at 0°C. What final temperature, in degrees Celsius, is needed to change the volume of the gas to ea
Diano4ka-milaya [45]

Answer:

A = -213.09°C

B = 15014.85 °C

C = -268.37°C

Explanation:

Given data:

Initial volume of gas = 5.00 L

Initial temperature = 0°C  (273 K)

Final volume = 1100 mL, 280 L, 87.5 mL

Final temperature = ?

Solution:

Formula:

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Conversion of mL into L.

Final volume = 1100 mL/1000 = 1.1 L

Final volume =  87.5 mL/1000 = 0.0875 L

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

T₂ = V₂T₁ / V₁

T₂ = 1.1 L × 273 K / 5.00 L

T₂ = 300.3 L.K / 5.00 K

T₂ = 60.06 K

60.06 K - 273 = -213.09°C

2)

V₁/T₁ = V₂/T₂

T₂ = V₂T₁ / V₁

T₂ = 280 L × 273 K / 5.00 L

T₂ = 76440 L.K / 5.00 K

T₂ = 15288 K

15288 K - 273 = 15014.85 °C

3)

V₁/T₁ = V₂/T₂

T₂ = V₂T₁ / V₁

T₂ = 0.0875 L × 273 K / 5.00 L

T₂ = 23.8875 L.K / 5.00 K

T₂ = 4.78 K

4.78 K - 273 = -268.37°C

4 0
3 years ago
Which two energy sources were used the most in
Naily [24]

Answer:

The 1st and 2nd ones on the top

Explanation:

Hope this helps:)

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3 years ago
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