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Hoochie [10]
3 years ago
13

Which type of bonding involves the complete transfer of a valence electron from a less electronegative atom to a more electroneg

ative one?
Chemistry
2 answers:
Ivan3 years ago
6 0

Answer:

Ionic or electrovalent bonds

Explanation:

Ionic or electrovalent bonds are interatomic or intramolecular bonds which are formed between two kinds of atoms having a large electronegativity difference usually 2.1.

Electronegativity is the property that combines the ability of an atom to gain or lose electrons. It is expressed as the tendency with which atoms of elements attracts valence electrons in a chemical bond.

In this bond type, a metal transfers its electrons to a more electronegative atom which is a non-metal.

Mashcka [7]3 years ago
6 0

The answer is: a. ionic bonding.

Ionic bond is the electrostatic attraction between oppositely charged ions (cations and anions).  

(brainliest would be great)

For example, compound magnesium chloride (MgCl₂) has ionic bond.  

In this example, chlorine is large company, because it has greater electronegativity than magnesium (small company) and take electrons (assets) from it.

Magnesium (Mg) transfers two electrons, became positive cation, to chlorine (Cl), which became negative anion.  

Magnesium is metal from group 2 and chlorine is nonmetal from group 17 of the Periodic table.  

Electronegativity (χ) is a property that describes the tendency of an atom to attract a shared pair of electrons.

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fomenos

Answer: The volume of the balloon up there is 6.192 L.

Explanation:

Given: V_{1} = 1.80 L,    P_{1} = 785 mm Hg (mm Hg = 0.00131579) = 1.032 atm

P_{2} = 0.300 atm,       V_{2} = ?

Formula used to calculate volume is as follows.

P_{1}V_{1} = P_{2}V_{2}

Substitute the value into above formula as follows.

P_{1}V_{1} = P_{2}V_{2}\\1.032 atm \times 1.80 L = 0.300 atm \times V_{2}\\V_{2} = 6.192 L

Thus, we can conclude that the volume of the balloon up there is 6.192 L.

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Explanation:

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A city continuously disposes of effluent from a wastewater treatment plant into a river. The minimum flow in the river is 130 m3
Vera_Pavlovna [14]

Answer:

2.54\ \text{mg/L}

Explanation:

C = Allowable concentration = 1.1 mg/L

Q_1 = Flow rate of river = 130\ \text{m}^/\text{s}

Q_2 = Discharge from plant = 37\ \text{m}^3/\text{s}

C_1 = Background concentration = 0.69 mg/L

C_2 = Maximum concentration that of the pollutant

The concentration of the mixture will be

C=\dfrac{Q_1C_1+Q_2C_2}{Q_1+Q_2}\\\Rightarrow C_2=\dfrac{C(Q_1+Q_2)-Q_1C_1}{Q_2}\\\Rightarrow C_2=\dfrac{1.1(130+37)-130\times 0.69}{37}\\\Rightarrow C_2=2.54\ \text{mg/L}

The maximum concentration that of the pollutant (in mg/L) that can be safely discharged from the wastewater treatment plant is 2.54\ \text{mg/L}.

6 0
2 years ago
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