Answer:
There are 24*60 minutes in a day (ignoring the imperfections of the natural world, the Earth and Sun). So there are 24*60 valid 24 hour times (excluding seconds) on a digital clock.
A measure of time representing the interval between consecutive passages of the Sun across the meridian, averaged over one year. 1 day = 24 hr (86,400 sec) and 60 minutes.
hope it helps ya mate! :-P
Ethene (H2C=CH2) is a gaseous by-product of the long-chain hydrocarbons that are cracked to create highly sought-after goods like gasoline and aviation fuels.
<h3>What is ethene used for?</h3>
- The uses of ethene include: It is employed in the creation of polythene. It is used to make fruits artificially ripe.
- Ethene is also utilised to create other beneficial molecules such ethanol, oxyethylene flame, and ethylene glycol, which is used as an antifreeze.
<h3>Does ethylene resemble ethene?</h3>
- A substance having the chemical formula C2H4 is ethylene, commonly known as ethene.
- It is both the most easily manufactured organic compound in the world and the simplest alkene.
- Unsaturated hydrocarbon ethylene, often known as C2H4, is utilised in industrial facilities and is occasionally found in typical medicine cabinets as a hormone.
learn more about Ethene here
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Answer:
96%
Explanation:
To find the percent yield, we can use this equation
The actual yield of aspirin is 3.0 and the theoretical is 3.14 in this case, so just plug the numbers in.
Thus the percent yield is 96%
;)
Atoms can be divided more so thats not true. atoms from the same element arent all nesacarly identical because of isotopes
Answer:
65.08 g.
Explanation:
- For the reaction, the balanced equation is:
<em>2AlCl₃ + 3Br₂ → 2AlBr₃ + 3Cl₂,</em>
2.0 mole of AlCl₃ reacts with 3.0 mole of Br₂ to produce 2.0 mole of AlBr₃ and 3.0 mole of Cl₂.
- Firstly, we need to calculate the no. of moles of 36.2 grams of AlCl₃:
<em>n = mass/molar mass</em> = (36.2 g)/(133.34 g/mol) = <em>0.2715 mol.</em>
<u><em>Using cross multiplication:</em></u>
2.0 mole of AlCl₃ reacts with → 3.0 mole of Br₂, from the stichiometry.
0.2715 mol of AlCl₃ reacts with → ??? mole of Br₂.
∴ The no. of moles of Br₂ reacts completely with 0.2715 mol (36.2 g) of AlCl₃ = (0.2715 mol)(3.0 mole)/(2.0 mole) = 0.4072 mol.
<em>∴ The mass of Br₂ reacts completely with 0.2715 mol (36.2 g) of AlCl₃ = no. of moles of Br₂ x molar mass</em> = (0.4072 mol)(159.808 g/mol
) = <em>65.08 g.</em>
