Explanation:
It is known that for high concentration of , reduction will take place. As, cathode has a positive charge and it will be placed on left hand side.
Now, = 0 and the general reaction equation is as follows.
3.00 M n = 2 30 mM
E =
=
= 0.038 V
Therefore, we can conclude that voltage shown by the voltmeter is 0.038 V.
Answer:
There was 450.068g of water in the pot.
Explanation:
Latent heat of vaporisation = 2260 kJ/kg = 2260 J/g = L
Specific Heat of Steam = 2.010 kJ/kg C = 2.010 J/g = s
Let m = x g be the weight of water in the pot.
Energy required to vaporise water = mL = 2260x
Energy required to raise the temperature of water from 100 C to 135 C = msΔT = 70.35x
Total energy required =
Hence, there was 450.068g of water in the pot.