Answer:
The concentration of the most dilute solution is 0.016M.
Explanation:
First, a solution is prepared and then it undergoes two subsequent dilutions. Let us calculate initial concentration:
![[Na_{2}SO_{4}]=\frac{moles(Na_{2}SO_{4})}{liters(solution)} =\frac{mass((Na_{2}SO_{4}))}{molarmass(moles(Na_{2}SO_{4}) \times 0.100L)} =\frac{2.5316g}{142g/mol\times 0.100L } =0.178M](https://tex.z-dn.net/?f=%5BNa_%7B2%7DSO_%7B4%7D%5D%3D%5Cfrac%7Bmoles%28Na_%7B2%7DSO_%7B4%7D%29%7D%7Bliters%28solution%29%7D%20%3D%5Cfrac%7Bmass%28%28Na_%7B2%7DSO_%7B4%7D%29%29%7D%7Bmolarmass%28moles%28Na_%7B2%7DSO_%7B4%7D%29%20%5Ctimes%200.100L%29%7D%20%3D%5Cfrac%7B2.5316g%7D%7B142g%2Fmol%5Ctimes%200.100L%20%7D%20%3D0.178M)
<u>First dilution</u>
We can use the dilution rule:
C₁ x V₁ = C₂ x V₂
where
Ci are the concentrations
Vi are the volumes
1 and 2 refer to initial and final state, respectively.
In the first dilution,
C₁ = 0.178 M
V₁ = 15 mL
C₂ = unknown
V₂ = 50 mL
Then,
<u>Second dilution</u>
C₁ = 0.053 M
V₁ = 15 mL
C₂ = unknown
V₂ = 50 mL
Then,
Answer:
ionization energy is the amount of energy it takes to remove an atoms most loosely bound electron. going from the top of a group to the bottom, ionization energy decreases, as it is getting easier and easier to remove the outermost electron. As you move down a group, you add principle energy levels, which causes shielding. this means that there is decreased communication between the outermost electron and the nucleus, making it easier to remove the outer electron.
Answer: yes
Explanation:
even in combined state, radioactive elements continue to emit radiation spontaneously. For instance RaCl2 is still radioactive because of the radium content of the compound. This is applied positively in radionuclides used to study chemical reactions or uptake of certain elements in then body.
The answer to this question is false
This is a physical change, you can turn the current off not changing something permanently such as mixing cake batter you cant delude the eggs and flour so its would be physical.
