A sample of 3.62 moles of diphosphorous trioxide is
1 answer:
Answer:
B
Explanation:
This question is about stoichiometry. From the balanced equation ⇒
, we see that 3 moles of water is needed to react with 1 mole of
.
This means that, to fully react 3.62 moles of , we would need 3*3.62 or 10.86 moles of water. However, we only have 6.31 moles, so water is the limiting reactant.
Since 3 moles of water react with 1 mole of , 6.31 moles of water can fully react with 6.31÷3 or 2.1033 moles of
.
From the balanced equation, we see that every mole of reacted gets you 2 moles of
. Therefore, 2.1033 moles of
would give you approximately 4.21 moles of
.
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Explanation:
We will balance equation which describes the reaction between sulfuric acid and sodium bicarbonate: as follows.
Next we will calculate how many moles of are present in 85.00 mL of 1.500 M sulfuric acid.
As, Molarity =
1.500 M =
n = 0.1275 mol
Now set up and solve a stoichiometric conversion from moles of to grams of
. As, the molar mass of
is 84.01 g/mol.
= 21.42 g
So unfortunately, 15.00 grams of sodium bicarbonate will "not" be sufficient to completely neutralize the acid. You would need an additional 6.42 grams to complete the task.