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BARSIC [14]
3 years ago
7

A uniform thin rod is hung vertically from one end and set into small amplitude oscillation. If the rod has a length of 3.6 m, t

his rod will have the same period as a simple pendulum of length ____ cm. Round your answer to the nearest whole number.
Physics
1 answer:
salantis [7]3 years ago
3 0

Answer:

The length of the simple pendulum is 2.4 meters.

Explanation:

Time period of simple pendulum is given by :

T=2\pi\sqrt{\dfrac{L}{g}}

L is the length of pendulum

The time period of the rope is given by :

T=2\pi\sqrt{\dfrac{2L'}{3g}}

L' is the length of the rod, L' = 3.6 m

It is given that, the rod have the same period as a simple pendulum and we need to find the length of simple pendulum i.e.

2\pi\sqrt{\dfrac{L}{g}}=2\pi\sqrt{\dfrac{2L'}{3g}}

On solving the above equation as :

\dfrac{L}{g}=\dfrac{2L'}{3g}

L = 2.4 m

So, the length of the thin rod that is hung vertically from one end and set into small amplitude oscillation 2.4 meters. Hence, this is the required solution.

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By v = u - at 
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One end of a rope is tied to the handle of a horizontally-oriented and uniform door. a force f is applied to the other end of th
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For rotational equilibrium of the door we can say that torque due to weight of the door must be counter balanced by the torque of external force

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here weight will act at mid point of door so its distance is half of the total distance where force is applied

here we know that

mg = 145 N

now we will have

F = \frac{mg}{2}

F = \frac{145}{2} = 72.5 N

so our applied force is 72.5 N

7 0
4 years ago
A train slows down as it pulls into a station. if the train is moving from your left to your right, what are the directions of t
navik [9.2K]

The directions of the vectors for velocity and acceleration are in the opposite directions.

  • The velocity vector is always in the direction of motion of the object. So, the direction of velocity is in the right from our point of view.
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Velocity vector is the rate of change of position of an object. Acceleration vector is the rate of change of velocity of an object.

Therefore, the directions of the vectors for velocity and acceleration are in the opposite directions.

To know more about velocity and acceleration vectors

brainly.com/question/13492374

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3 0
2 years ago
An object is dropped from a height of 75.0 m above ground level. (a) Determine the distance traveled during the first second. (b
lys-0071 [83]

Answer:

a)Distance traveled during the first second = 4.905 m.

b)Final velocity at which the object hits the ground = 38.36 m/s

c)Distance traveled during the last second of motion before hitting the ground = 33.45 m

Explanation:

a) We have equation of motion

             S = ut + 0.5at²

     Here u = 0, and a = g

              S = 0.5gt²

    Distance traveled during the first second ( t =1 )

              S = 0.5 x 9.81 x 1² = 4.905 m

   Distance traveled during the first second = 4.905 m.

b)  We have equation of motion

            v² = u² + 2as

      Here u = 0, s= 75 m and a = g

           v² = 0² + 2 x g x 75 = 150 x 9.81

           v = 38.36 m/s

      Final velocity at which the object hits the ground = 38.36 m/s

c) We have S = 0.5gt²

                   75 = 0.5 x 9.81 x t²

                    t = 3.91 s

   We need to find distance traveled last second

   That is

          S = 0.5 x 9.81 x 3.91² - 0.5 x 9.81 x 2.91² = 33.45 m

   Distance traveled during the last second of motion before hitting the ground = 33.45 m

       

3 0
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garik1379 [7]

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Therefore the vectors are measured in one or several dimensions that include a magnitude and an address.

The correct option is the last:

"<em>a measurement in more than one dimension that includes a magnitude and a direction</em>"

5 0
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