A uniform thin rod is hung vertically from one end and set into small amplitude oscillation. If the rod has a length of 3.6 m, t
1 answer:
Answer:
The length of the simple pendulum is 2.4 meters.
Explanation:
Time period of simple pendulum is given by :
L is the length of pendulum
The time period of the rope is given by :
L' is the length of the rod, L' = 3.6 m
It is given that, the rod have the same period as a simple pendulum and we need to find the length of simple pendulum i.e.
On solving the above equation as :
L = 2.4 m
So, the length of the thin rod that is hung vertically from one end and set into small amplitude oscillation 2.4 meters. Hence, this is the required solution.
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Answer:
C) Pressure will compress a gas, reducing its volume and giving it a greater density and concentration of particles.
Explanation:
At constant temperature, pressure and volume are inversely related.
P V = constant
As the pressure increases, the gas compresses, the particles come closer reducing the volume of gas.
As we know, with decrease in volume, density increases.
Thus, the pressure of a gas is directly related to concentration of particles. Increase in pressure causes increase in concentration of the particles.
If you illustrate the problem, you will somewhat come up with the figure shown. The missing value is the hypotenuse of the right triangle. Using the pythagorean theorems, the value is determined to be
x = √(0.7^2 + 2.4^2)
x = 2.5 km
2.5 km is the magnitude of the distance. If you want to incorporate the displacement, the answer is reported as 2.5 km, southeast. The direction is determined from the starting point to the endpoint.
x = √(0.7^2 + 2.4^2)
x = 2.5 km
2.5 km is the magnitude of the distance. If you want to incorporate the displacement, the answer is reported as 2.5 km, southeast. The direction is determined from the starting point to the endpoint.