A uniform thin rod is hung vertically from one end and set into small amplitude oscillation. If the rod has a length of 3.6 m, t
1 answer:
Answer:
The length of the simple pendulum is 2.4 meters.
Explanation:
Time period of simple pendulum is given by :
L is the length of pendulum
The time period of the rope is given by :
L' is the length of the rod, L' = 3.6 m
It is given that, the rod have the same period as a simple pendulum and we need to find the length of simple pendulum i.e.
On solving the above equation as :
L = 2.4 m
So, the length of the thin rod that is hung vertically from one end and set into small amplitude oscillation 2.4 meters. Hence, this is the required solution.
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Explanation:
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Answer:
, the minus meaning west.
Explanation:
We know that linear momentum must be conserved, so it will be the same before () and after (
) the explosion. We will take the east direction as positive.
Before the explosion we have .
After the explosion we have pieces 1 and 2, so .
These equations must be vectorial but since we look at the instants before and after the explosions and the bomb fragments in only 2 pieces the problem can be simplified in one dimension with direction east-west.
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So for our values we have: