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I am Lyosha [343]
3 years ago
10

A train brakes from 25 m/s to rest in 30 sec. What is its deceleration?

Physics
1 answer:
givi [52]3 years ago
8 0

Answer:

a= -0.83m\s^2

Explanation:

a = v \ t

a = -25 \ 30 = -0.833 m\s^2

the object is slowing down 0.83 meter every second

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A car travels 240km in 4h what’s the cars velocity
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The car's speed is 240km/4hr= 60km/hr.

There's not enough information given in the question to determine its velocity.

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3 years ago
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What happens if :<br> . The test charge is not tiny.
docker41 [41]

The magnitude of the test charge must be small enough so that it does not disturb the issuance of the charges whose electric field we wish to measure otherwise the metric field will be different from the actual field.

<h3>How does test charge affect electric field?</h3>

As the quantity of authority on the test charge (q) is increased, the force exerted on it is improved by the same factor. Thus, the ratio of force per charge (F / q) stays the same.

Adjusting the amount of charge on the test charge will not change the electric field force.

<h3>What is a test charge used for?</h3>

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To learn more about test charge, refer

brainly.com/question/16737526

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3 0
2 years ago
Which of the following elements has the smallest atomic radius?
kondor19780726 [428]
Fluorine it has a atomic radius of 42 
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3 years ago
17. Which of the following is NOT a testable
Artemon [7]

Answer:

c. testing student opinions

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opinions aren't factual and they would not aide an experiment if it wasn't for a social experiment.

7 0
3 years ago
A football player runs from his own goal line to the opposing team's goal line, returning to his forty-yard line, all in 22.4 s.
Bumek [7]
I assume L=120 yards as the length of the football field.

1) The average speed is given by the total distance covered by the player divided by the time taken.
The total distance covered to go from one goal line to the other and then back to the 40-yards line is
S=120y+(120-40)y=120y+80y=200 y
And the time taken is t=22.4 s, so the average speed of the player is
v= \frac{S}{t}= \frac{200 y}{22.4 s}=8.93 y/s

2) The find the average velocity, we should also consider the direction (and the sign) of the velocity.
In the the first part of the motion, the player goes from one goal line to the other one, so he covers 120 y. However, in the second part of the motion he goes back by 80 y. Therefore, the net displacement of the player is
S=120 y-80 y=40 y
and so, the average velocity is
v= \frac{S}{t}= \frac{40 y}{22.4 s}= 1.79 y/s
6 0
3 years ago
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