Answer with Explanation:
We are given that
Diameter=d=22.6 cm
Mass,m=426 g=
1 kg=1000 g
Radius,r=
1m=100 cm
Height,h=5m

a.By law of conservation of energy






Where 
b.Rotational kinetic energy=
Rotational kinetic energy=8.35 J
Answer:
Cork
Explanation:
Cork is a solid, other ones are fluid.
Be heavier
density=mass÷volume
if two items have the same size they have the same volume so the heavier one will be the denser one
Answer:

Explanation:
Here two charges are placed at distance "d" apart
now the net value of electric field at some position between two charges will be ZERO
so we will have
electric field due to charge 1 = electric field due to charge 2

Let the position where net field is zero will lie at distance "r" from q1

now we will have

now square root both sides

now we have

so we have

Answer:
D. creates radioactive waste.
Explanation:
Nuclear energy can create nuclear radioactive waste