Answer:
Explanation:
Given
Initial speed 
distance traveled before coming to rest 
using equation of motion

where v=final velocity
u=initial velocity
a=acceleration
s=displacement

for 
using same relation we get

divide 1 and 2 we get


So a distance if 213.32 ft is required to stop the vehicle with 80 mph speed
Explanation:
Using Newtons second law on each block
F = m*a
Block 1

Block 2

Block 3

Solving Eq1,2,3 simultaneously
Divide 1 and 2

Put Eq 4 into Eq3

Put Eq 5 into Eq2 and solve for a

Substitute back in Eq2 and use Eq4 and solve for T2 & T1

Answer:
Balancing of forces,
In the X-direction:
-Tcos4.5^o +Tcos4.5^o=0
In the Y-direction:
Tsin4.5^o +Tsin4.5^o-m*g=0
2Tsin4.5^o=15*9.81
T=(15*9.81)/(2sin4.5^o)
=937.75 N
Therefore, tension in the rope is 937.75 N.
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