The image is missing, so i have attached it.
Answer:
The force exerted on the large block by the small block = 8.4 N
Explanation:
From the image attached, the mass of the small block = 2M while the mass of the large block = 3M
Also,Force on small block = F and force on large block = 2F
Equilibrium of forces on the left gives;
2F - N = 3Ma
Thus,
Ma = (2F - N)/3 - - - - eq1
Also, on right hand side, Equilibrium of forces gives;
N - F = 2Ma
Ma = (N - F)/2 - - - - eq2
Equating eq(1) and eq(2) gives us;
(2F - N)/3 = (N - F)/2
Where N is the force exerted on the large block by the small block.
Making N the subject gives;
4F - 2N = 3N - 3F
5N = 7F
N = 7F/5
We are given F = 6N
Thus;
N = 7(6)/5
N = 8.4 N
am sorry i thout this was my question not your answer sorry
Answer:
12.02 m/s north of east
Explanation:
Let be the horizontal and vertical velocity of the 3rd piece, positive in the East and North direction. Also let m be the mass of the 2 smaller pieces, so 2m is the mass of the 3rd piece.
We can solve for the 2 velocities components using law of momentum conservation. Before the explosion, the total momentum was 0 because the coconut was at rest. After the explosion:
- In the x direction:
negative 17 because 1 piece flew west
- In the y direction
negative 17 because 1 piece flew south
So the speed and direction of the 3rd piece is
north of east
<span>-2,5SD = 2.1%
</span>first u need to find number of standard deviations and look up on table what percentage that is