<span>The strong nuclear force holds the nucleons together. If there is an imbalance between the two forces, the nucleus will decay. ... When protons and neutrons forma nucleus, energy is released. This energy is called the nuclear binding energy. Thisenergy comes from the conversion of a small amount of mass into energy.</span>
Answer:
the ratio of the deuteron's orbital radius to the proton's orbital radius is 2 : 1
Explanation:
Detailed explanation and calculation is shown in the image below
Work is equal to a force over a distance and is equal to the change in kinetic energy, so
<span>
- Fd=ΔKE
</span>
<span>−Fd=1/2m<span>v22</span>−1/2m<span>v21</span></span>
<span>d=(1/2m<span>v22</span>−1/2m<span>v21</span>)/−F
</span>
We know that Ffric=kFnatural and Fnatural=mg so:
<span>d=(1/2m<span>v22</span>−1/2m<span>v21</span>)/−(k∗mg)</span><span>d=(−1/2<span>v21</span>)/−(k∗g)
</span><span>d=(−1/2×(14.6m/s<span>)2</span>)/−(0.137×9.8m/s)
</span><span>
d = 78.9m</span>
It’s B can I have twenty points
<u>Answer:</u>
Horizontal component of the velocity when the opposing player fields the ball = 11.00 m/s
<u>Explanation:</u>
The velocity of a body in 2 dimension can be resolved in to 2 parts, horizontal and vertical component. In the case of free falling or projectile body the horizontal component remains the same but vertical component is affected by acceleration due to gravity.
In this case Initial velocity = 17.6 m/s
Angle between horizontal axis and direction of velocity = 51.3 °
We know that horizontal component = v cos θ
Vertical component = v sin θ
Since the horizontal component remains the same, it is unchanged when the opposing player fields the ball.
So horizontal component of the velocity = v cos θ = 17.6 * cos 51.3 °
= 11.00 m/s
