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natta225 [31]
3 years ago
14

An object is placed at 0 on a number line. It moves 3 units to the right, then 4 units to the left, and then 6 units to the righ

t. The displacement of the object is
Physics
2 answers:
Usimov [2.4K]3 years ago
7 0

Answer:

Explanation:

The correct answer is: +5

Explanation:

An object is placed at 0; it means:

Initial position of the object = 0.

Now it moves to 3 units to right, so keeping the standard cartesian coordinate system in mind (in right right x-axis is positive and left x-axis is right), the new position of the object will be +3.

Object now moves 4 units to the left, it means +3 - 4 = -1; object is at the position -1.

Object then moves 6 units to the right, therefore,

Final position of the object = -1 + 6 = +5.

Displacement = Final position - Initial position

Displacement = +5 - 0 = +5

Read more on Brainly.com - brainly.com/question/847612#readmore

Verdich [7]3 years ago
6 0

The correct answer is: +5

Explanation:

An object is placed at 0; it means:

Initial position of the object = 0.

Now it moves to 3 units to right, so keeping the standard cartesian coordinate system in mind (in right right x-axis is positive and left x-axis is right), the new position of the object will be +3.

Object now moves 4 units to the left, it means +3 - 4 = -1; object is at the position -1.

Object then moves 6 units to the right, therefore,

Final position of the object = -1 + 6 = +5.

Displacement = Final position - Initial position

Displacement = +5 - 0 = +5

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The tension in the horizontal towrope pulling a water-skier is 250 N while the skier moves due west a distance of 50 m. How much
icang [17]

Answer:

W = 250(50) = 12500 J

Explanation:

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3 years ago
An electric fan has the power output of 60W. How much work is done if the fan operates for 120s?
Digiron [165]
Since power = work done/time, 60= work done/120, work done = 120*60 = 7200. So,work done = 7200N (Newton). 
I'm not sure if you're supposed to convert the seconds to time.
4 0
3 years ago
Air is being blown into a spherical balloon at the rate of 1.68 in.3/s. Determine the rate at which the radius of the balloon is
NISA [10]

Answer: 0.006in/s

Explanation:

Let the rate at which air is being blown into a spherical balloon be dV/dt which is 1.68in³/s

Also let the rate at which the radius of the balloon is increasing be dr/dt

Given r = 4.7in and Π = 3.14

Applying the chain rule method

dV/dt = dV/dr × dr/dt

If the volume of the sphere is 4/3Πr³

V = 4/3Πr³

dV/dr = 4Πr²

If r = 4.7in

dV/dr = 4Π(4.7)²

dV/dr = 277.45in²

Therefore;

1.68 = 277.45 × dr/dt

dr/dt = 1.68/277.45

dr/dt = 0.006in/s

7 0
2 years ago
A 35.4 kg girl is riding on the back of a 15.23 kg cart. the cart and the kid are both moving eastward at 4.25 m/s when she step
Grace [21]

Answer:

The final  velocity of the cart is  v_c = 7.02 \  m/s

Explanation:

From the question we are told that

    The mass of the girl is  m_g  = 35.4 \ kg

     The mass of the cart is  m_c  = 15.23 \ kg

      The speed of the cart and  kid(girl) is  v = 4.25 \ m/s

     The final velocity of  the girl is v_g  = 3.06 \  m/s

Let assume that velocity eastward is  positive and velocity westward is negative (Note that if we assume vise versa it wouldn't affect the answer )

   The total momentum of the system before she steps off the back of the cart

is mathematically evaluated as

        p__{T1}} = (m_g + m_c) * v

substituting values

        p__{T1}} = (35.4 + 15.23) * 4.25

        p__{T1}} =215.17 \  kg m /s

The total momentum after she steps off the back of the cart is mathematically evaluated as

        p__{T2}} = (m_g * v_g ) +(  m_c * v_c )

Where  v_c  is the final velocity of the cart

substituting values    

      p__{T2}} = (35.4 * 3.06 ) +(  15.23 * v_c )

       p__{T2}} = 108. 324 + 15.23  v_c

Now according to the law of conservation of momentum

       p__{T1}} =p__{T2}}

So  

       215.17 \  kg m /s =  108. 324 + 15.23  v_c

=>      v_c = 7.02 \  m/s

Since the value is positive it implies that the cart moved eastward

7 0
3 years ago
In the process of photosynthesis, how do plants obtain the water, carbon dioxide, and energy they use for this process?
NNADVOKAT [17]

Answer:

They get it from the air and soil. They also take energy from the sun.

Explanation:

During photosynthesis, plants take in carbon dioxide (CO2) and water (H2O) from the air and soil.

3 0
2 years ago
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