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2 years ago

5

Bandura found that children who witnessed aggressive behavior being punished were far more likely to be aggressive than children

who did not. please select the best answer from the choices provided t f

1 answer:

Sonbull [250]2 years ago

7 0

Answer:

The evidence is conclusive; aggression and violence in the media lead to aggression and violence in the general population.

Explanation:

good luck

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How does compression (the force) work? Not tension and compression. Just compression.

Eddi Din [679]

<span>What allows an arch bridge to span greater distances than a beam bridge, or a suspension bridge to stretch over a distance seven times that of an arch bridge? The answer lies in how each bridge type deals with the important forces of compression and tension.</span>

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3 years ago

A 30⁰ 5.2 km 3.7 km FIGURE 1 40⁰ B x FIGURE 1 shows two displacement vector A and B. Determine the magnitude and direction of th

Alika [10]

The resulatant displacement will be 8.60m

What is displacement?

Displacement is the shortest path covered by an individual.

We have given the distance 5.2km and 3.7Km.

The resultant will be given in the photo

to learn more about displacement click brainly.com/question/13413762

8 0

2 years ago

Three metal fishing weights, each with a mass of 1.00x102 g and at a temperature of 100.0°C, are placed in 1.00x102 g of water a

worty [1.4K]

Answer:

Approximately $0.253\; {\rm J \cdot g^{-1} \cdot K^{-1}}$ assuming no heat exchange between the mixture and the surroundings.

Explanation:

Consider an object of specific heat capacity $c$ and mass $m$ . Increasing the temperature of this object by $\Delta T$ would require $Q = c\, m \, \Delta T$ .

Look up the specific heat of water: $c(\text{water}) = 4.182\; {\rm J \cdot g^{-1} \cdot K^{-1}}$ .

It is given that the mass of the water in this mixture is $m(\text{water}) = 1.00 \times 10^{2}\; {\rm g}$ .

Temperature change of the water: $\Delta T(\text{water}) = (45 - 35)\; {\rm K} = 10\; {\rm K}$ .

Thus, the water in this mixture would have absorbed :

$\begin{aligned}Q &= c\, m\, \Delta T \\ &= 4.182\; {\rm J \cdot g^{-1}\cdot K^{-1}} \\ &\quad \times 1.00 \times 10^{2}\; {\rm g} \times 10\; {\rm K} \\ &= 4.182 \times 10^{3}\; {\rm J}\end{aligned}$ .

Thus, the energy that water absorbed was: $Q(\text{water}) = 4.182 \times 10^{3}\; {\rm J}$ .

Assuming that there was no heat exchange between the mixture and its surroundings. The energy that the water in this mixture absorbed, $Q(\text{water})$ , would be the opposite of the energy that the metal in this mixture released.

Thus: $Q(\text{metal}) = -Q(\text{water}) = -4.182 \times 10^{3}\; {\rm J}$ (negative because the metal in this mixture released energy rather than absorbing energy.)

Mass of the metal in this mixture: $m(\text{metal}) = 3 \times 1.00 \times 10^{2}\; {\rm g} = 3.00 \times 10^{2}\; {\rm g}$ .

Temperature change of the metal in this mixture: $\Delta T(\text{metal}) = (100 - 45)\; {\rm K} = 55\; {\rm K}$ .

Rearrange the equation $Q = c\, m \, \Delta T$ to obtain an expression for the specific heat capacity: $c = Q / (m\, \Delta T)$ . The (average) specific heat capacity of the metal pieces in this mixture would be:

$\begin{aligned}c &= \frac{Q}{m\, \Delta T} \\ &= \frac{-4.182 \times 10^{3}\; {\rm J}}{3.00 \times 10^{2}\; {\rm g} \times (-55\; {\rm K})} \\ &\approx 0.253\; {\rm J \cdot g^{-1} \cdot K^{-1}}\end{aligned}$ .

6 0

2 years ago

Mental processes refers to

hjlf

Internal,covert processes

5 0

3 years ago

As galáxias são maiores do que os enxames de estrelas?

GuDViN [60]

$▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Responder \;\;a}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪$

As galáxias são geralmente maiores do que os aglomerados de estrelas. Como disse Geller ~ As galáxias são como as cidades em que vivem os aglomerados de estrelas. As galáxias podem ter cerca de milhares ou mais aglomerados de estrelas ~

I hope it helps ~

8 0

3 years ago