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AleksAgata [21]
3 years ago
5

How can understanding velocity help to prevent a mid-air collision

Physics
1 answer:
dsp733 years ago
7 0

Answer:

To maintain enough time to prevent a collision, a system operating in air traffic where aircraft speed does not

fall below 100 km/h (most medium-sized UAVs and GA aircraft) will need to be able to detect obstacles which

subtend an arc-width of as small as 0.125 mra

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What kind of waves are present during an earthquake? ...
Brrunno [24]

Answer:

1. The two main types of waves are body waves and surface waves. Body waves can travel through the earth's inner layers, but surface waves can only move along the surface of the planet like ripples on water. Earthquakes radiate seismic energy as both body and surface waves.

2. potential energy

3. Newton's second law of motion is F = ma, or force is equal to mass times acceleration.

4. Refraction is the bending of light

5. Density uses the formula p=m/V, or density (p) is equal to mass (m) divided by volume (V). Density is defined as mass per unit volume.

Explanation:

6 0
3 years ago
how large can the kinetic energy of an electron be that is localized within a distance (change in) x = .1 nmapproximately the di
elena-14-01-66 [18.8K]

Answer:

The kinetic energy of an electron is 1.54\times10^{-15}\ J

Explanation:

Given that,

Distance = 0.1 nm

We need to calculate the momentum

Using uncertainty principle

\Delta x\Delta p\geq\dfrac{h}{4\pi}

\Delta p\geq\dfrac{h}{\Delta x\times 4\pi}

Where, \Delta p = change in momentum

\Delta x = change in position

Put the value into the formula

\Delta p=\dfrac{6.6\times10^{-34}}{4\pi\times10^{-10}}

\Delta p=5.3\times10^{-23}

We need to calculate the kinetic energy for an electron

K.E=\dfrac{p^2}{2m}

Where, P = momentum

m = mass of electron

Put the value into the formula

K.E=\dfrac{(5.3\times10^{-23})^2}{2\times9.1\times10^{-31}}

K.E=1.54\times10^{-15}\ J

Hence, The kinetic energy of an electron is 1.54\times10^{-15}\ J

4 0
3 years ago
Hydrogen is an example of a<br> 1<br> A.metal<br> B.noble gas<br> C.nonmetal<br> D.metalloid
miskamm [114]

Answer:

Hydrogen is a nonmetal.

Explanation:

To be assure look at the periodic

table and the groups

5 0
4 years ago
An object accelerates from rest to 85m/s over a distance of 36m. What acceleration did it experience?
Marizza181 [45]
Suvat
we have s, u, v and we want a
the suvat equation with these values in is: v^2 = u^2 - 2as
so a = (-v^2 + u^2)/-2s 
plug numbers in
a = (-85^2 + 0^2)/-2*36 = 7225/72 = 100.3... ms^-2
6 0
4 years ago
A 10.3 kg block of ice slides without friction down a long track. The start of the track is 4.2 m higher than the end of the tra
Agata [3.3K]
Hello

1) Since there is no friction between the ice and the track, there is no loss of energy in the motion, so we can apply the law of conservation of energy.
The total energy E (sum of potential energy P and kinetic energy K) must be conserved:
E=P+K  

2) At the beginning of the motion, the total energy of the object is just potential energy:
E_1=P=mgh 
where m is the mass, g=9.81~m/s^2 is the gravitational acceleration, and h=4.2~m is the initial height of the body.

3) At the end of the motion, this potential energy has converted into kinetic energy, and so the total energy at this point is 
E_2= \frac{1}{2}mv^2
where m is the mass and v is the final velocity of the object.

4) We said that the total energy must be conserved, therefore we can write
E_1 = E_2
and so:
mgh= \frac{1}{2}mv^2
from which we can find v, the velocity:
v= \sqrt{2gh}= \sqrt{2\cdot9.81~m/s^2 \cdot 4.2~m}=9.08~m/s
8 0
4 years ago
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