How much NH4Cl can you dissolve in 200 g of water at 90° to make a saturated solution?
C) 140
Answer is Manganese(ii) chloride
To answer this, you need to know the charges for both Mn and Cl
Mn is in the transition metal category and is unique with having 3 levels of charges
manganese - MN
Manganese(ii) - Mn^2+
Manganese(iii) - Mn^3+
Cl is a nonmetal with the standard charge of Cl^-1
Since you have two charges that don't cancel out, they get switched.
So Cl would receive a positive 2. Because it was a positive 2, we can assume that it starts with Manganese(ii). Then we add chloride to the end of it as it ends with Cl.
Answer:
12.29 M
Explanation:
- The reaction that takes place is:
H₂SO₄ + 2NaOH → 2Na⁺ + SO₄⁻² + 2H₂O
- Now let's calculate the <u>moles of H₂SO₄ that were titrated</u>:
= 0.01229 mol H₂SO₄.
- Thus, the <u>concentration of the diluted solution is</u>:
0.01229 mol H₂SO₄ / 0.010 L = 1.229 M
- Finally, the <u>concentration of the original acid solution is:</u>
= 12.29 M