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kolbaska11 [484]
3 years ago
11

Difference between pulling and pushing force​

Physics
1 answer:
Mrac [35]3 years ago
7 0

Answer:

Push and pull both are forces , but the difference is in their direction at which it is applied . If the force applied in the direction of motion of the particle then we call it as push . If that force applied in the direction OPPOSITE to the motion of particle then it is termed as pull

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A quantity of a gas is an absolute pressure of 400 K PA in the absolute temperature of 110° Kelvin when the temperature of the g
aliina [53]

Given:

P1 = 400 kPa
T1 = 110 K

T2 = 235K

Required:

P2

Solution:

Apply Gay-Lussac’s law where P/T = constant

P1/T1 = P2/T2

P2 = T2P1/T1

P2 = (235K)(400kPa) / (110K)

P2 = 855 kPa

4 0
4 years ago
A 13-N east horizontal force acts in the same direction as a 6.4kg block as it slides 2.5m/s on a frictionless, horizontal surfa
MaRussiya [10]

Answer:

6.77 m/s

Explanation:

Acceleration = Force/mass;

The block is accelerated by 13/6.4 m/s^2 for 2.1s from an initial velocity of 2.5m/s.

Applying the equation of motion:

Vf=Vi + at

Where Vf is the final velocity, Vi is the initial velocity, a is the acceleration and t is the time for which the object accelerates.

<h3>Vf= 2.5 + ((13/6.4)*2.1);</h3>
8 0
3 years ago
Why is density equal to mass/volume?
Zepler [3.9K]

Answer:

This is because both the mass and the volume of the two minerals will be added, and so when they are divided to get the density the result will be between the two. Typical densities for gasses are on the order of thousandths of grams per cubic centimeter

Explanation:

4 0
3 years ago
Before colliding the momentum of block A is +15.0 kg*m/s, and block B is -35.0 kg*m/s. after, block A has a momentum -12.0 kg*m/
UkoKoshka [18]

The momentum of block B afterwards is -8.0 kg m/s.

Explanation:

We can solve this problem by applying the principle of conservation of momentum.

In fact, the total momentum before and after the collision must be conserved. Therefore, we can write:

p_A + p_B = p_A' + p_B'

where:

p_A = +15.0 kg m/s is the initial momentum of block A

p_B = -35.0 kg m/s is the initial momentum of block B

p_A' = -12.0 kg m/s is the final momentum of block A

p_B' is the final momentum of block B

Solving for p_B', we find:

p_B' = p_A + p_B - p_A' = +15.0 +(-35.0) - (-12.0)=-8.0 kg m/s

So, the momentum of block B afterwards is -8.0 kg m/s.

Learn more about momentum:

brainly.com/question/7973509

brainly.com/question/6573742

brainly.com/question/2370982

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#LearnwithBrainly

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3 years ago
________ is the si unit of angular momentum
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Answer:

kg m2/s

Explanation:

I think it is :)

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3 years ago
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