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lisov135 [29]
2 years ago
10

Suppose 4 J of work are needed to stretch a spring 14 cm from its natural position. How much work is needed to stretch it 20 cm

from its natural position
Physics
1 answer:
Tamiku [17]2 years ago
7 0

Answer:

8.16 J

Explanation:

Applying,

W = ke²/2................. Equation 1

Where W = work done in stretching the spring, k = spring constant, e = extension

make k the subject of the equation

k = 2W/e²................ Equation 2

From the question,

Given: W = 4 J, e = 14 cm = 0.14 m

Substitute these values into equation 2

k = 2(4)/0.14²

k = 8/0.0196

k = 408.16 N/m

If stretchd 20 cm from its natural length,

Therefore,

e = 20 cm = 0.2 m

W = 408.16(0.2²)/2

W = 8.16 J

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An object is hanging by a string from the ceiling of an elevator. The elevator is moving upward with a constant speed. What is t
xeze [42]

Answer:

The magnitude of the tension in he string is equal to the magnitude of the weight of the object.

Explanation:

According to the Newton's 1st law, An object will remain at rest or in uniform motion in a straight line unless acted upon by an unbalanced force.

In here, the elevator is moving with a constant speed. So the object must have the equal constant speed. Which means, it has a uniform motion. According to Newton's 1st law, the total unbalanced force on the object must be zero . As we know, there are only two forces are on the object and they are,

The tension in string(T)   ,   The weight of the object(W) .

                                  ∴ F    =   0

                                 T  -  W  =   0

So to balanced those forces, the magnitude of the tension in the string must be equal to the magnitude of the weight of  the object.  

       

8 0
3 years ago
What's the frequency of a wave with a wavelength of 10 and velocity of 200m/s?
uranmaximum [27]

Answer:

\boxed {\boxed {\sf 20 \ Hz}}

Explanation:

The frequency of a wave can be found using the following formula.

f=\frac{v}{\lambda}

where <em>f</em> is the frequency, <em>v</em> is the velocity/wave speed, and λ is the wavelength.

The wavelength is 10 meters and the velocity is 200 meters per second.

  • 1 m/s can also be written as 1 m*s^-1

Therefore:

v= 200 \ m*s^{-1} \\\lambda = 10 \ m

Substitute the values into the formula.

f=\frac{200 \ m*s^{-1}}{10 \ m}

Divide and note that the meters (m) will cancel each other out.

f=\frac{200 \ s^{-1}}{10 \ }

f=20 \ s^{-1}

  • 1 s^-1 is equal to Hertz
  • Therefore, our answer of 20 s^-1 is equal to 20 Hz

f= 20 \ Hz

The frequency of the wave is <u>20 Hertz</u>

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C) alternately increase and decrease
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How many miles must you travel to make the Earth fall the same amount?
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In other words, the baseball falls as it did before, but the ball is moving so fast that the curvature of the Earth becomes a factor and the Earth "falls away" from the ball. So, theoretically, if a pitcher on a 100 foot (30.48 m) high hill threw a ball straight and fast enough,the ball would circle the Earth at exactly 100 feet and hit the pitcher in the back of the head once it circled the globe! The bad news for the person throwing the ball is that the ball will be traveling at the same speed as when they threw it, which is about 8 km/s or several times faster than a rifle bullet. This would be very bad news if it came back and hit the pitcher, but we'll get to that in a minute.

4 0
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What does the path of an object look like when it is in uniform motion ?
alexandr1967 [171]
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