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lisov135 [29]
3 years ago
10

Suppose 4 J of work are needed to stretch a spring 14 cm from its natural position. How much work is needed to stretch it 20 cm

from its natural position
Physics
1 answer:
Tamiku [17]3 years ago
7 0

Answer:

8.16 J

Explanation:

Applying,

W = ke²/2................. Equation 1

Where W = work done in stretching the spring, k = spring constant, e = extension

make k the subject of the equation

k = 2W/e²................ Equation 2

From the question,

Given: W = 4 J, e = 14 cm = 0.14 m

Substitute these values into equation 2

k = 2(4)/0.14²

k = 8/0.0196

k = 408.16 N/m

If stretchd 20 cm from its natural length,

Therefore,

e = 20 cm = 0.2 m

W = 408.16(0.2²)/2

W = 8.16 J

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Answer:17.08 s

Explanation:

Given

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Second runner need to run a distance of 250+45.6=295.6 m

Time required by second runner t=\frac{295.6}{4.65}=63.56 s

time required by first runner to reach finish line=\frac{250}{3.1}=80.64 s

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4 years ago
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R=\frac{\rho L}{A}

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A plane leaves Hartsfield Airport and flies around the world returning to Hartsfield airport What is the planes displacement?
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The way around the world
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Answer:

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According to the question,

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