k = spring constant of the spring = 100 N/m
m = mass hanging from the spring = 0.71 kg
T = Time period of the spring's motion = ?
Time period of the oscillations of the mass hanging is given as
T = (2π) √(m/k)
inserting the values in the above equation
T = (2 x 3.14) √(0.71 kg/100 N/m)
T = (6.28) √(0.0071 sec²)
T = (6.28) (0.084) sec
T = 0.53 sec
hence the correct choice is D) 0.53
Answer:
<em>126.01 rad/s^2</em>
<em></em>
Explanation:
since it starts from rest, initial angular speed ω' = 0 rad/s
angular speed N = 477 rev/min
angular speed in rad/s ω =
=
= 49.95 rad/s
angular displacement ∅ = 1.5758 rev
angular displacement in rad/s =
= 2 x 3.142 x 1.5758 = 9.9 rad
angular acceleration
= ?
using the equation of angular motion
ω^2 = ω'^2 + 2
∅
imputing values, we have

2495 = 19.8
= 2495/19.8 = <em>126.01 rad/s^2</em>
<span>A full moon is at its brightest, and here is no disk to be seen. New moons are barely visable.</span>
Answer:
D. 48.985 N
Explanation:
Newton's second law states that:

which means that the net force acting on an object is equal to the product between the object's mass and its acceleration.
The equation of the forces for the briefcase in the elevator therefore is given by:

where
N is the normal reaction exerted on the briefcase
(mg) is the weight of the briefcase, with
m = 4.5 kg being its mass
g = 9.8 m/s^2 is the acceleration of gravity
a = 1.10 m/s^2 is the acceleration
Here we chose upward as positive direction.
Solving for N, we find the normal force:

So the closest answer is
D. 48.985 N
The distance from mile-mark 10 to mile-mark 115 is (115-10) = 105 miles.
Speed = (distance covered) / (time to cover the distance) .
Speed = (105 miles) / (1.75 hours)
Speed = (105/1.75) (mi/hr)
<em>Speed = 60 mph</em> (B)