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fomenos
2 years ago
7

In a heat engine, 700 J of heat enters the system, and the piston does 400 J of work. What is the final internal (thermal) energ

y of the system if the initial energy is 1200 J? 300 J 900 J 1100 J 1500 J.
Chemistry
2 answers:
MAVERICK [17]2 years ago
6 0

Answer: The answer would be: 1500 J

Explanation:

took the quiz

Vitek1552 [10]2 years ago
4 0

The first law of thermodynamics characterises the two types of energy transfer, as heat and as thermodynamic. The final internal (thermal) energy of the system is 1,500 J.

<h3>What is internal energy?</h3>

The energy present in a system itself for conducting reactions is called internal energy.

Given,

  • Heat entering system (Q) = 700 J
  • Work done by the piston (W) = 400
  • Initial energy (\rm U_{1})= 1200 J

According to the <u>first law of thermodynamics</u>:

\rm Q = \Delta U + W

Substituting values in the above equation:

\begin{aligned}\rm Q &= \rm U_{2} - U_{1} + W\\\\\rm U_{2}  &= \rm Q - W + U_{1}\\\\\rm U_{2}  &= 700 - 400 + 1200\\\\&= 1500 \;\rm J\end{aligned}

Therefore, option D. 1500 J is the final energy.

Learn more about internal energy here:

brainly.com/question/2602565

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C.) No, because the Moon reflects most of the Sun's light rather than

absorbing it

Explanation:

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8 0
3 years ago
11. In TLC analysis of ferrocene and acetylferrocene (on silica TLC plate) which prediction is correct: A) ferrocene is more pol
yaroslaw [1]

Answer:

Alternative C would be the correct choice.

Explanation:

  • The dual compounds were evaluated on something like a TLC plate through three separate additives in conducting a TLC study of ferrocene versus acetylferrocene.
  • The polar as well as nonpolar ferrocene where nonpolar is about 0.63 with the maximum R_f value, and indeed the polar is somewhere around 0.19 with R_f.
  • TLC plate (30:1 toluene/ethanol) established with.  

The other three choices are not related to the given circumstances. So that option C would be the appropriate choice.

8 0
2 years ago
n the diagram shown, when an object ‘X’ is brought near the ring shaped magnet, the magnet moves away from it. Four friends are
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6 0
2 years ago
__Mg +_ AgNO3 → _Mg(NO3)2 + __Ag
damaskus [11]

<em><u>Mg + 2AgNO3 = Mg(NO3)2 + 2Ag</u></em><em><u>.</u></em>

<em><u>....</u></em>

3 0
2 years ago
A 100.0 g sample of aluminum released 1680 calories when cooled from 100.0c to 20.0 c what is the specific heat of the metal
vovangra [49]

Answer:

The specific heat of aluminium is 0.8792 J/g °C  or 0.21 Cal/g °C

Explanation:

Step 1 : Write formule of specific heat

Q=mcΔT

with Q = heat transfer (J)

with m = mass of the substance

with c = specific heat ⇒ depends on material and phase ( J/g °C)

with ΔT = Change in temperature

For this case :

Q = 1680 Calories = 7033.824 J ( 1 calorie = 4.1868 J)

m = 100.0g

c= has to be determined

ΔT = 100 - 20 = 80°C

<u>Step 2:  Calculating specific heat</u>

⇒ via the formule Q=mcΔT

7033.824 J = 100g * c * 80

7033.824 = 8000 *c

c = 7033.824 /8000

c = 0,879228 J/g °C

or 0.21 Cal / g°C

The specific heat of aluminium is 0.8792 J/g °C  or 0.21 Cal/g °C

6 0
3 years ago
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