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fomenos
2 years ago
7

In a heat engine, 700 J of heat enters the system, and the piston does 400 J of work. What is the final internal (thermal) energ

y of the system if the initial energy is 1200 J? 300 J 900 J 1100 J 1500 J.
Chemistry
2 answers:
MAVERICK [17]2 years ago
6 0

Answer: The answer would be: 1500 J

Explanation:

took the quiz

Vitek1552 [10]2 years ago
4 0

The first law of thermodynamics characterises the two types of energy transfer, as heat and as thermodynamic. The final internal (thermal) energy of the system is 1,500 J.

<h3>What is internal energy?</h3>

The energy present in a system itself for conducting reactions is called internal energy.

Given,

  • Heat entering system (Q) = 700 J
  • Work done by the piston (W) = 400
  • Initial energy (\rm U_{1})= 1200 J

According to the <u>first law of thermodynamics</u>:

\rm Q = \Delta U + W

Substituting values in the above equation:

\begin{aligned}\rm Q &= \rm U_{2} - U_{1} + W\\\\\rm U_{2}  &= \rm Q - W + U_{1}\\\\\rm U_{2}  &= 700 - 400 + 1200\\\\&= 1500 \;\rm J\end{aligned}

Therefore, option D. 1500 J is the final energy.

Learn more about internal energy here:

brainly.com/question/2602565

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You have a graduated cylinder with 10 mL of water in it.
Law Incorporation [45]

Answer:

<h3>The answer is 10 g/mL</h3>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume} \\

From the question

mass = 300 g

volume = final volume of water - initial volume of water

volume = 40 - 10 = 30 mL

We have

density =  \frac{300}{30}  =    \frac{30}{3}  \\

We have the final answer as

<h3>10 g/mL</h3>

Hope this helps you

5 0
3 years ago
What is acid sulfuric's function ?​
masya89 [10]

Answer:

The answer is below

Explanation:

Sulfuric acid is used for various purposes, some of which include the following:

1. It is used in the production of various manufactured goods.

2. It is used in the manufacturing of chemicals

3. It is also used in the making of fertilizer

4. It is used in the refining process of petroleum products

5. It is used in the processing of metals

3 0
3 years ago
What is the volume of 1.56 kg of a compound whose molar mass is 81.86 g/mole and whose density is 41.2 g/ml?
hjlf

Answer:

v = 37.9 ml

Explanation:

Given data:

Mass of compound = 1.56 kg

Density = 41.2 g/ml

Volume of compound = ?

Solution:

First of all we will convert the mass into g.

1.56 ×1000 = 1560 g

Formula:

D=m/v

D= density

m=mass

V=volume

v = m/d

v =  1560 g / 41.2 g/ml

v = 37.9 ml

7 0
3 years ago
Which factor has the least effect on the rate of solution of a solid in a liquid?
vitfil [10]
The pressure will not affect the rate of solution.
4 0
3 years ago
Read 2 more answers
An exponent of "2" means that if we double the concentration of the reactant the rate doubles as well Exponents in rate laws are
Karo-lina-s [1.5K]

Answer:

- False.

- False.

- True.

- True.

Explanation:

Hello, for each statement we state:

- An exponent of "2" means that if we double the concentration of the reactant the rate doubles as well.

FALSE because considering a rate law like:

-r=kC^2

The exponent of "2" powers the concentration to the second power, not doubles the rate law, thus, if C is 3, for k=1, r will be -9. On the other hand if the rate is like:

-r=kC

The rate will be -3, that is why the rate is not doubled when the "2" in concentration is present.

- Exponents in rate laws are based on the coefficients from the balanced equation.

FALSE because for nonelemental chemical reactions, the exponents do not match with each species' stoichiometric coefficients in the rate law.

- The rate constant, k, takes into account the effect of activation energy and temperature on the reaction.

TRUE, since the Arrhenius equation allows us to prove the effect of the activation energy and the temperature:

k=Aexp(-\frac{Ea}{RT})

- Differential rate laws allow us to compare concentration and time.

TRUE as they are given like:

\frac{1}{\nu _A} \frac{dC_A}{dt} =\frac{1}{\nu _B} \frac{dC_B}{dt} =...

Best regards.

5 0
3 years ago
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