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alexdok [17]
3 years ago
11

Determine the work done by an ideal gas while expanding by a volume of 0.25 L against an external pressure of 1.50 atm (assume a

diabatic conditions, i.e., no heat exchange during the expansion).
Chemistry
1 answer:
Sliva [168]3 years ago
6 0

Answer : The value of work done by an ideal gas is, 37.9 J

Explanation :

Formula used :

Expansion work = External pressure of gas × Volume  of gas

Expansion work = 1.50 atm × 0.25 L

Expansion work = 0.375 L.atm

Conversion used : (1 L.atm = 101.3 J)

Expansion work = 0.375 × 101.3 = 37.9 J

Therefore, the value of work done by an ideal gas is, 37.9 J

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6) A 0.20 ml CO2 bubble in a cake batter is at 27°C. In the oven it gets
Nata [24]

Answer: The new volume of cake is 1.31 mL.

Explanation:

Given: V_{1} = 0.20 mL,         T_{1} = 27^{o}C

V_{2} = ?,                    T_{2} = 177^{o}C

Formula used to calculate new volume is as follows.

\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}

Substitute the values into above formula as follows.

\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}\\\frac{0.20 mL}{27^{o}C} = \frac{V_{2}}{177^{o}C}\\V_{2} = 1.31 mL

Thus, we can conclude that the new volume of cake is 1.31 mL.

5 0
3 years ago
Part A
astraxan [27]

Answer

mass of 1 mole = 18g

mass of 1 mL = 1g

the unit used is gram

Explanation:

There are two ways to find mass of water:

1st way:

If we find Mass of water for one mole of water:

For this purpose we use mole formula as below

                          no. of moles = mass in grams / molar mass

if we find mass for one mole of water:

then

no. of moles of water = 1 mol

molar mass of water = H₂O = (1x2 +1x16) = 18 g/mol

mass of water = ?

Put the value in the mole formula

          no. of moles = mass in grams / molar mass . . . . . . . . . . . . (1)

by rearranging the formula (1)

            mass in grams = no. of moles x molar mass

            mass in grams = 1 mole x 18 g/mol

            mass in grams =  18 g

So for one mole of water the mass of water is 18 g and the unit for it is gram.

2nd way:

We can find mass of water by another way too

if we find the mass 1 mL of water

then the formula will be used is

                              D = m/v

where D is density

m is the mass

and v is the volume

So

density of water for 1 mL (D) = 1 g/ml

volume of water = 1 mL

mass of water = ?

By Rearranging density formula for mass

                                m = D/v ......................... (2)

put the values in equation 2

                                m= 1gmL⁻¹ / 1 mL

                                 m= 1g

So the mass of 1mL is 1g

7 0
3 years ago
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