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alexdok [17]
3 years ago
11

Determine the work done by an ideal gas while expanding by a volume of 0.25 L against an external pressure of 1.50 atm (assume a

diabatic conditions, i.e., no heat exchange during the expansion).
Chemistry
1 answer:
Sliva [168]3 years ago
6 0

Answer : The value of work done by an ideal gas is, 37.9 J

Explanation :

Formula used :

Expansion work = External pressure of gas × Volume  of gas

Expansion work = 1.50 atm × 0.25 L

Expansion work = 0.375 L.atm

Conversion used : (1 L.atm = 101.3 J)

Expansion work = 0.375 × 101.3 = 37.9 J

Therefore, the value of work done by an ideal gas is, 37.9 J

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Explanation:

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What is the word equation of photodecomposition?​
Oksi-84 [34.3K]

Answer:

I have for Decompostion

Explanation:

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3 years ago
A chemical test has determined the concentration of a solution of an unknown substance to be 2.41 M. a 100.0 mL volume of the so
Oksana_A [137]

Answer : The molar mass of unknown substance is, 39.7 g/mol

Explanation : Given,

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Formula used :

\text{Molarity}=\frac{\text{Mass of unknown substance}\times 1000}{\text{Molar mass of unknown substance}\times \text{Volume of solution (in mL)}}

Now put all the given values in this formula, we get:

2.41M=\frac{9.56g\times 1000}{\text{Molar mass of unknown substance}\times 100.0mL}

\text{Molar mass of unknown substance}=39.7g/mol

Therefore, the molar mass of unknown substance is, 39.7 g/mol

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Sandy puts a paper clip on the table. Then, she puts a magnet near the paperclip. The paperclip begins to move.
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Applied forces/or unbalanced:i hope that helps you
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If I had another ball on a 10ft slide, it would have twice the potential energy the first ball had.

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Basically, <em>Potential</em> is the "build up" but it does not, I repeat does not move.

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7 0
4 years ago
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