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nataly862011 [7]
3 years ago
6

Sepuede compartir los vienes si tu mujer sefue con otro

Chemistry
1 answer:
makvit [3.9K]3 years ago
7 0
Si se Casaron por vienes separdos no tienes porque compartir.
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Explain why liquids and gases differ in density and ability to be compressed ?
EastWind [94]
Gases are less dense and the molecules are farther apart which means that it can be compressed
7 0
3 years ago
Read 2 more answers
A box contains identical balls of which 12 are red, 18 white and 8 blue. Three balls are drawn from the box one after the other
svet-max [94.6K]

Answer:

a) 12/323

b) 8/233

Explanation:

a) The probability of a red ball being drawn is 12/38, or in a simplified fraction, 6/19. To find the probability that 3 are red you would multiply the probability of the fraction for each, except subtracting one from the total each time as the drawn is done without replacement. This is done as follows: 6/19 × 6/18 × 6/17= 12/323

b) The probability of drawing a blue ball is 8/38, or 4/19. To find that the first one is blue and the rest are red, the equation is done as follows: 4/19 × 6/18 × 6/17 = 8/233

(hopefully I did this right)

8 0
3 years ago
If some of the gas bubbles from the reaction had escaped out the bottom of the tube, how would this have affected your value for
Andrej [43]

The composition would be more "diluted" in a sense.

7 0
3 years ago
How do the particles in each state of matter move
hodyreva [135]

the particles of solids move but very slowly.

the particles of liquids move moderately fast

the particles of gas move very fast.

The reasons for this movement is the space the particles are together. Since there is not move space between solids, the particles move slowly, water there is moderate space, and air there is a lot of space.

7 0
3 years ago
While heating up a 25 gram sample of concrete (specific heat = 0.210-cal/g°C), your initial tempărature is room temperature (25°
Lana71 [14]

Answer:

Final temperature  = 83.1 °C

Explanation:

Given data:

Mass of concrete = 25 g

Specific heat capacity = 0.210 cal/g. °C

Initial temperature = 25°C

Calories gain = 305 cal

Final temperature = ?

Solution:

Q = m. c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = T2 - T1

305 cal = 25 g ×0.210 cal/g.°C × T2 -  25°C

305 cal = 5.25cal/°C × T2 -  25°C

305 cal / 5.25cal/°C = T2 -  25°C

58.1 °C = T2 -  25°C

T2 = 58.1 °C + 25°C

T2 = 83.1 °C

7 0
2 years ago
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