11 lb = 4.99 kg.
So, 74.85 mg should be given to the infant. Thus 0.75 mL of the suspension should be given.
Dissociation of NaCl in water is given as below,
NaCl ₍s₎ → Na⁺ ₍aq₎ + Cl⁻ ₍aq₎
According to this balanced equation the moles on RHS and LHS are as,
Moles on LHS,
NaCl ₍s₎ = 1 Mole
Moles on RHS,
Na⁺ ₍aq₎ = 1 Mole
Cl⁻ ₍aq₎ = 1 Mole
Result:
<span>When one mole of sodium chloride dissociates in water, it produces 2 Moles of Ions.</span>
The molar solubility is 7.4×
M and the solubility is 7.4× g/L .
Calculation ,
The dissociation of silver bromide is given as ,
→ 
+ 
S
- S S
Ksp = [ ] [ ] = [S] [ S ] = 
S = √ Ksp = √ 5. 5×
= 7.4×
The solubility =7.4× g/L
The molar solubility is the solubility of one mole of the substance.
Since , one mole of is dissociates and form one mole of each and ion . So, solubility is equal to molar solubility but unit is different.
Molar solubility = 7.4× mol/L = 7.4× M
To learn more about molar solubility ,
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Cells have many structure inside of them called organelles which allow it to function and survive
Hope it helps
