99.9224 % of the acid is not ionized.
____HA + H₂O ⇌ A⁻ + H₃O⁺
I: ___<em>c</em> ________0 ____0
C: _-α<em>c</em> _______+α<em>c</em> __+α<em>c
</em>
E: <em>c</em>(1-α) _______α<em>c</em> ___α<em>c
</em>
pH = 4.110
[H₃O⁺] = α<em>c</em> = 10^(-4.110) mol/L = 7.76 × 10⁻⁵ mol/L
α = 7.76 × 10⁻⁵
1 – α = 1 - 7.76 × 10⁻⁵ = 0.999 224 = 99.9224 %
Answer:
the answer is water
Explanation:
During photosynthesis, plants take in carbon dioxide (CO2) and water (H2O) from the air and soil. Within the plant cell, the water is oxidized, meaning it loses electrons, while the carbon dioxide is reduced, meaning it gains electrons. This transforms the water into oxygen and the carbon dioxide into glucose.
Answer:
[HOCH₂CH₂OH] = 24.1 m
Explanation:
Ethylene glycol → HOCH₂CH₂OH
60% by mass means that 60 g of ethylene glycol are contained in 100 g of solution.
Solution mass = Solute mass + Solvent mass
100 g = 60 g + Solvent mass
Solvent mass = 40 g
Molality are the moles of solute contained in 1kg of solvent.
We determine the moles of solute → 60 g . 1mol/62 g = 0.967 moles
We convert the mass of solvent from g to kg → 40 g . 1kg/1000 g = 0.04 kg
Molality → 0.967 mol / 0.04 kg = 24.1 m
Answer:
the 2p5 should have filled up one more so it would be 2p6 ...which assuming it's not an excited electron?
