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deff fn [24]
3 years ago
9

There are 3 quarters, 4 dimes and 7 nickels in a change purse. Suppose 3 coins are selected without replacement. What is the pro

bability of selecting a quarter, then a dime, and then a nickel?
Mathematics
2 answers:
qwelly [4]3 years ago
6 0
Prob of just quarter is 3/14 for a dime is 4/14 and for a nickel its 7/14
then all you do is multiply them all together to get 306122449/<span>10000000000 that took me way to long</span>
Ket [755]3 years ago
5 0
0.037%

How I did it:

I did 3/13, and got 0.23, I didn't do 14 because if its going to be chosen, its going to have one less, and I did the same for the other ones. Then I simply just multiplied them.
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A movers ramp is placed on top
Salsk061 [2.6K]

Answer:

I think it would be 13 feet

Step-by-step explanation:

12*5=60

and sense it is a triangle you divide by 2 and get 30

<h3>30-12-5=13</h3><h3>this is what I think</h3>
4 0
3 years ago
Solve each triangle: Find all the missing sides and angles. Round answers to the nearest tenth.
horrorfan [7]

Step-by-step explanation:

let \: angle \: be \:  \alpha  \\  \tan( \alpha )  =  \frac{p}{b}  \\  \tan(69.9)  = \frac{9.7}{bc}  \\ bc =  \frac{9.7}{2.73}  \\ bc = 3.55 \\ by \: using \: pythagorean \: theorem \\ ab =  \sqrt{ {9.7}^{2} }  +  {2.73}^{2}  \\ ab = 10.07

3 0
1 year ago
The comprehensive strength of concrete is normally distributed with μ = 2500 psi and σ = 50 psi. Find the probability that a ran
VARVARA [1.3K]

Answer:

The probability that the diameter falls in the interval from 2499 psi to 2510 psi is 0.00798.

Step-by-step explanation:

Let's define the random variable, X = "Comprehensive strength of concrete". We have information that X is normally distributed with a mean of 2500 psi and a standard deviation of  50 psi (or a variance of 2500 psi). In other words, X \sim N(2500, 2500).

We want to know the probability of the mean of X or \bar{X} that falls in the interval [2499;2510]. From inference theory we know that :

\bar{X} \sim N(2500, \frac{2500}{5}) \Rightarrow \bar{X} \sim N(2500,500)

Now we can find the probability as follows:

P(2499 \leq \bar{X} \leq 2510) \Rightarrow P(\frac{2499 - 2500}{500} \leq \frac{\bar{X} - 2500}{500} \leq \frac{2499 - 2500}{500} ) \Rightarrow\\\Rightarrow P(-0.002 \leq \frac{\bar{X} - 2500}{500} \leq 0.02 ) \Rightarrow P(-0.002 \leq Z \leq 0.02 )

Where Z \sim N(0,1), then:

P(-0.002 \leq Z \leq 0.02 ) \approx P(0 \leq Z \leq 0.02 ) = P(Z \leq 0.02 ) - P(Z \leq 0) \\P(0 \leq Z \leq 0.02 ) = 0.50798 - 0.5 = 0.00798

8 0
3 years ago
On a coordinate plane, a line connects (negative 4, negative 5) and (negative 2, negative 4), a curve connects (negative 2, nega
statuscvo [17]

Answer: f^-1(4)= 2 f^-1(-5)= -4 f^-1(0)= 0

Step-by-step explanation:

6 0
3 years ago
 (6,-3) and y = - 6x - 3
Hatshy [7]
Wait what's the question tho?
is it if this point is on the line?
cause it's not
-y=mx+b
3=-6(6)-3
-3=-36-3
-3 does not equal -39
hence, point is not on the line
3 0
3 years ago
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