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deff fn [24]
3 years ago
9

There are 3 quarters, 4 dimes and 7 nickels in a change purse. Suppose 3 coins are selected without replacement. What is the pro

bability of selecting a quarter, then a dime, and then a nickel?
Mathematics
2 answers:
qwelly [4]3 years ago
6 0
Prob of just quarter is 3/14 for a dime is 4/14 and for a nickel its 7/14
then all you do is multiply them all together to get 306122449/<span>10000000000 that took me way to long</span>
Ket [755]3 years ago
5 0
0.037%

How I did it:

I did 3/13, and got 0.23, I didn't do 14 because if its going to be chosen, its going to have one less, and I did the same for the other ones. Then I simply just multiplied them.
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Please help me, it's due today!
m_a_m_a [10]

Answer:

I believe it is -123

Step-by-step explanation:

you have to replace all the x's with -4 so you would do the equation -6(-4)^2+8(-4)+5

-6(-4)^2 is -96

-96+8(-4) is -128

-128+5 is -123

4 0
1 year ago
Read 2 more answers
The swimming pool is open when the high temperature is higher than 20^\circ\text{C}20 ? C20, degree, C. Lainey tried to swim on
Svetlanka [38]

Answer:

30-3d\leq 20

Step by step explanation:

Let d represent the rate of temperature decrease in degrees Celsius per day from Monday to Thursday.  

As temperature decreased at a constant rate in the next 3 days, so the rate of temperature will decrease 3d degree Celsius in 3 days.  

We are told that the pool was open on Monday. The high temperature was 30^{\circ}{\text{C} on Monday. So the decrease in temperature from Monday to Thursday will be 30-3d.

We have been given that the swimming pool is open when the high temperature is higher than 20^{\circ}{\text{C}.

As the pool was closed on Thursday. This means that temperature on Thursday was less than or equal to 20 degree Celsius. We can represent this information in an inequality as:

30-3d\leq 20

Therefore, the inequality 30-3d\leq 20 can be used to determine the rate of temperature decrease in degrees Celsius per day, d, from Monday to Thursday.

5 0
4 years ago
2tan(45-A)/1+tan^2(45-A)=cos2a
AVprozaik [17]

Answer:

Let θ = (45 - A)°.

=> 2Tanθ/ 1 + Tan²θ

=> 2Sinθ/Cosθ / 1 + Sin²θ / Cos²θ

=> 2Sinθ/Cosθ/ Cos²θ + Cos²θ / Cos²θ

=> 2Sinθ/Cosθ/ 1 / Cos²θ

=> 2SinθCos²θ/Cosθ

=> 2SinθCosθ  

=> Sin2θ

But we assumed θ = (45 - A)°,

=> Sin2(45 - A)

=> Sin(90  - 2A)  (∵ Sin(90 - θ) = Cosθ)

=> Cos2A

= R.H.S

Hence proved.

Step-by-step explanation:

3 0
3 years ago
IMPORTANT!!!
AURORKA [14]
C & A I believe because 2+3 is 5 so that’s 5x
5 0
3 years ago
Look at attachment inside please help me im on timer
Julli [10]

4x { }^{2}  + 5 +  \frac{27}{x + 5}
3 0
4 years ago
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