Answer:
640.5
Explanation: i got it right on acellus
Answer:
60 V
Explanation:
Let the potential on capacitor be V . This will be equal to voltage of the source .
During discharge this voltage of capacitor will create current .
V / 120 = .5
V = 60 V
So this would have been the voltage of the source . So voltage of source
= 60 V
b- electrons are shared between two atoms
Thank you for posting your question here at brainly. I think your question is incomplete. Below is the complete question, it can be found elsewhere:
What is the probability of finding an electron within one Bohr radius of the nucleus?<span>Consider an electron within the 1s orbital of a hydrogen atom. The normalized probability of finding the electron within a sphere of a radius R centered at the nucleus is given by 1-a0^2[a0^2-e^(-2R/a0)(a0^2+2a0R+2R2)]. Where a0 is the Bohr radius (for a hydrogen atom, a0 = 0.529 Å.). What is the probability of finding an electron within one Bohr radius of the nucleus? What is the probability of finding an electron of the hydrogen atom within a 2.30a0 radius of the hydrogen nucleus?
Below is the answer:
</span><span>you plug the values for A0 and R into your formula</span>
Answer:
false
Explanation:
I'm pretty sure that's false.
