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miss Akunina [59]
3 years ago
15

*PLEASE HELP*

Physics
2 answers:
Westkost [7]3 years ago
5 0

Answer:

640.5

Explanation: i got it right on acellus

mr_godi [17]3 years ago
3 0

Answer:

641

Explanation:

not trying to bum the previous answer but this is the correct answer rounded to the 3rd sig fig

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If an object is thrown in an upward direction from the top of a building 1.6 x 10^2 ft. high at an initial velocity of 21.82 mi/
Goshia [24]

If an object is thrown in an upward direction from the top of a building 1.60 x 102 ft. high at an initial velocity of 21.82 mi/h, what is its final velocity when it hits the ground? (Disregard wind resistance. Round answer to nearest whole number and do not reflect negative direction in your answer.)


this question is troubling me i guessed 96 ft/s

can someone help me out and explain it thanks so much!!!!!!



7 0
3 years ago
Read 2 more answers
A solid conducting sphere of radius 2 cm has a charge of 8microCoulomb. A conducting spherical shell of inner radius 4 cm andout
nika2105 [10]

Answer:

C) 7.35*10⁶ N/C radially outward

Explanation:

  • If we apply the Gauss'law, to a spherical gaussian surface with radius r=7 cm, due to the symmetry, the electric field must be normal to the surface, and equal at all points along it.
  • So, we can write the following equation:

       E*A = \frac{Q_{enc} }{\epsilon_{0}} (1)

  • As the electric field must be zero inside the conducting spherical shell, this means that the charge enclosed by a spherical gaussian surface of a radius between 4 and 5 cm, must be zero too.
  • So, the +8 μC charge of  the solid conducting sphere of radius 2cm, must be compensated by an equal and opposite charge on the inner surface of the conducting shell of total charge -4 μC.
  • So, on the outer surface of the shell there must be a charge that be the difference between them:

        Q_{enc} = - 4e-6 C - (-8e-6 C) = + 4 e-6 C

  • Replacing in (1) A = 4*π*ε₀, and Qenc = +4 μC, we can find the value of E, as follows:

      E = \frac{1}{4*\pi*\epsilon_{0} } *\frac{Q_{enc} }{r^{2} } = \frac{9e9 N*m2/C2*4e-6C}{(0.07m)^{2} } = 7.35e6 N/C

  • As the charge that produces this electric field is positive, and the electric field has the same direction as the one taken by a positive test charge under the influence of this field, the direction of the field is radially outward, away from the positive charge.
6 0
3 years ago
Alex pushes on a 2.0 kg book, resulting in a net force of 6.0 N on the book.
Yakvenalex [24]

Answer:

<h2>3.0 m/s²</h2>

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

a  = \frac{f}{m}  \\

From the question we have

a =  \frac{6}{2}  \\

We have the final answer as

<h3>3.0 m/s²</h3>

Hope this helps you

4 0
3 years ago
2. Michelle bought 15.6 yards of fabric. She used 5.43 yards in her art 10 points
viktelen [127]
Do find the percentage you:
5.43/15.6=0.34

Time by 100:
34%

Closest answer is 35%

Hope this helps ;)
8 0
3 years ago
a ball is thrown with an initial velocity of 80 feet per second, at an angle of 40 degrees with the horizontal. Find the vertica
Scorpion4ik [409]
Well velocity is a vector quanity and we can brake vectors in to verticle and horizantal componontes threw these two formulas Vcostheta=Vx and Vsintheta=Vy
7 0
3 years ago
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